What is the time lapse between seeing a lightning strike and hearing the thunder if the lightning flash is 47 km away? The speed
1 answer:
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This is the explanation
The correct answer is option B. i.e. 60 ohm.
The diagram is attached.
Since all the resistances are attached in series.
Hence, the total resistance will be the sum of all resistances.
R_total = R_1+R_2+ R_3
= 10+20+30
= 60 ohms.
Therefore, option c is correct answer.
The diagram is attached.
Since all the resistances are attached in series.
Hence, the total resistance will be the sum of all resistances.
R_total = R_1+R_2+ R_3
= 10+20+30
= 60 ohms.
Therefore, option c is correct answer.
The complete question is;
Within the green dashed circle shown in the figure below, the magnetic field changes with time according to the expression B = 6.00t³ − 1.00t² + 0.800, where B is in teslas, t is in seconds, and R = 2.20 cm.
(a) When t = 2.00 s, calculate the magnitude of the force exerted on an electron located at point P1, which is at a distance r1 = 5.7 cm from the center of the circular field region.
I have attached the figure the question talks about.
Answer:
Force = 4.62 x 10^(-20) N
Explanation:
First of all,
∮E.ds = (d/dt)∮B.dA
E∮ds = (d/dt)B∮dA
dA is the area where B is not equal to zero.
Thus,
E•2πr = (d/dt)B•πR²
|E| = [(d/dt)B•πR²]/2πr
F = |qE| = q[(d/dt)B•πR²]/2πr
Where q is charge on electron = 1.6 x 10^(-19) C
F is magnitude of force exerted on electron
F = 1.6 x 10^(-19)[(d/dt)B•R²]/2r
F = 0.8 x 10^(-19)[(d/dt)B•R²]/r
Now, dB/dt = 18t² - 2t
Thus,
F = 0.8 x 10^(-19)[(18t² - 2t)•R²]/r
Thus, at t=2 and R=2.2cm = 0.022m and r = 5.7cm = 0.057m
Thus,
F = 0.8 x 10^(-19)[(18x2²) - (2x2)•(0.022²)]/(0.057)
F = (0.8 x 10^(-19) x 0.032912)/0.057 = 4.62 x 10^(-20) N
