Answer:
Q = 29.4 x 10⁻⁹ C.
Explanation:
Electric field due to a charge Q at distance d is given by coulomb law as follows
Electric field
E = k Q /d²
where for air k which is a constant is 9 x 10⁹
Given E = 32.08 , d = 2.84 m
Putting these values in the relation above, we have
![[tex]32.08=\frac{9\times 10^9\times Q}{(2.84)^2}](https://tex.z-dn.net/?f=%5Btex%5D32.08%3D%5Cfrac%7B9%5Ctimes%2010%5E9%5Ctimes%20Q%7D%7B%282.84%29%5E2%7D)
[/tex]
Q = 29.4 x 10⁻⁹ C.
Answer:
A. The pressure denoted as Pa and Pb at the surfaces of A and B in the tube is
PA= Pgas
PB= Patmos
B. The second sketch
C. The gas pressure is
Pgas= Patmos+ rho.g(h2-h1)
= 1atm + rho.g (h2-h1)
Explanation:
There all diffrent speeds
B. kinetic energy increases and potential energy decreases
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