Answer:
140 ml
Step-by-step explanation:
Let x be the amount of water in Beaker X and y be the amount of water in Beaker Y.
<u>Then we get following equations:</u>
<u>First part</u>
- x - 50 = 3/7(y + 50)
- 7x -350 = 3y + 150
- 7x = 3y + 500
<u>Second part</u>
- x + 100 = 4(y - 100)
- x + 100 = 4y - 400
- x = 4y - 500
<u>Substitute x in first equation:</u>
- 7(4y - 500) = 3y + 500
- 28y - 3500 = 3y + 500
- 28y - 3y = 500 + 3500
- 25y = 4000
- y = 4000/25
- y = 160 ml
<u>Then finding x:</u>
- x = 4*160 - 500
- x = 640 - 500
- x = 140 ml
Initial amount of water in Beaker X is 140 ml, in Beaker Y is 160 ml
(f o g o h)(x) = f { g [ h(x) ] }
Which means: apply first function h, then apply function g to the result, and finally apply function f to the new result.
h(25) = √25 = 5
g(5) = 5 - 3 = 2
f(2) = 3(2) = 6.
Answer: 6
Step-by-step explanation:
y = x - 4 and y = 4x + 2
=> x - 4 = 4x + 2
=> 3x = -6
=> x = -2
y = x - 4 = (-2) - 4 = -6
The solutions are x = -2 and y = -6.
What about it? What is the question?