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hoa [83]
3 years ago
6

A restaurant offers the soup of the day in 10 ounce servings. Suppose 85 customers ordered the soup of the day on Monday. To the

nearest tenth, how many gallons of the soup were sold on Monday?
A) 4.8 gallons
B) 5.5 gallons
C) 6.6 gallons **
D) 7.4 gallons
Mathematics
2 answers:
Natalija [7]3 years ago
8 0

Answer:

C) 6.6 gallons

Step-by-step explanation:

10oz * 85 = 850oz

There are 128 ounces in a gallon.

850/128 = 6.64

nata0808 [166]3 years ago
7 0

Answer:  Option 'c' is correct.

Step-by-step explanation:

Since we have given that

Number of servings = 85

Number of ounces per serving = 10 ounce

Total number of ounces would be

85\times 10\\\\=850

As we know that

1 gallon = 128 ounces

So, Number of gallons of the soup were sold on Monday would be \

\dfrac{850}{128}\\\\=6.64\\\\\approx 6.6 \ gallons

Hence, Option 'c' is correct.

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Given that you mention the divergence theorem, and that part (b) is asking you to find the downward flux through the disk x^2+y^2\le3, I think it's same to assume that the hemisphere referred to in part (a) is the upper half of the sphere x^2+y^2+z^2=3.

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\vec r(u,v)=\sqrt3\cos u\sin v\,\vec\imath+\sqrt3\sin u\sin v\,\vec\jmath+\sqrt3\cos v\,\vec k

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Then the upward flux of \vec F=(2z+2)\,\vec k through C is

\displaystyle\iint_C\vec F\cdot\mathrm d\vec S=\int_0^{2\pi}\int_0^{\pi/2}((2\sqrt3\cos v+2)\,\vec k)\cdot(\vec r_v\times\vec r_u)\,\mathrm dv\,\mathrm du

\displaystyle=3\int_0^{2\pi}\int_0^{\pi/2}\sin2v(\sqrt3\cos v+1)\,\mathrm dv\,\mathrm du

=\boxed{2(3+2\sqrt3)\pi}

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\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath

with 0\le u\le\sqrt3 and 0\le v\le2\pi. Take the normal to D to be

\vec s_v\times\vec s_u=-u\,\vec k

Then the downward flux of \vec F through D is

\displaystyle\int_0^{2\pi}\int_0^{\sqrt3}(2\,\vec k)\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv=-2\int_0^{2\pi}\int_0^{\sqrt3}u\,\mathrm du\,\mathrm dv

=\boxed{-6\pi}

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so the volume integral is

2\displaystyle\iiint_H\mathrm dV

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