<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B5%5D%7B96x%20%7B2%7D%5E%7B2%7Dy%20%7D%20" id="TexFormula1" title=" \sqrt[5]{96x {

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Flura [38]

3 years ago

2}^{2}y } " alt=" \sqrt[5]{96x {2}^{2}y } " align="absmiddle" class="latex-formula">

Mathematics

1 answer:

Helga [31]3 years ago

5 0

The first step to solving this is to evaluate the power
$\sqrt[5]{96 x 4y}$
now you'll calculate the product
$\sqrt[5]{384y}$
finally,, simplify the radical
2 $\sqrt[5]{12y}$
this means that the correct answer to your question is 2 $\sqrt[5]{12y}$
let me know if you have any further questions
:)

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Pls pls help Show work :)

Natasha2012 [34]

9514 1404 393

Answer:

31.243 units

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you of the relationships between sides and angles in a right triangle. Using the attached figure, it is convenient to find the length of BE as an intermediate step in the solution.

Sin = Opposite/Hypotenuse

sin(30°) = BE/100

BE = 100·sin(30°)

Then ...

Tan = Opposite/Adjacent

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x = BE/tan(58°) = 100·sin(30°)/tan(58°)

x ≈ 31.243 . . . . units

_____

Comment on the figure

The intermediate problem in creating the figure was to locate point D. That was accomplished by locating point C on a line at an angle of 58° CCW from the horizontal, using point B as a center. Then D is the intersection of BC with the x-axis. BE is drawn perpendicular to the x-axis.

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