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nikitadnepr [17]
3 years ago
14

the length of a rectangle is 4 cm more than 3 times its width.the area of the rectangle is 15cm^2. 1)write a quadratic model to

represent this situation? 2) find the width of the rectangle

Mathematics
1 answer:
labwork [276]3 years ago
8 0

Answer:x=5/3,-3


Step-by-step explanation:


You might be interested in
What is the result of adding these two equations?
andre [41]

Answer:

x=103/265        y=18/53

Step-by-step explanation:

5x -9y=1-----------(i)

-7x+2y=-5-----------(ii)

Multiplying eq 1 with 7 gives

35x-63y=7---------eq(iii)

Multiplying eq 2 with 5 gives

-35x+10y=-25--------eq(iv)

adding eq 3 qnd eq 4

35x-63y-35x+10y=7-25

-53y=-18

y=18/53--------eq5

Putting the value of y from eq 5 in eq 1

5x-9(18/53)=-5

5x- 162/53=-5

5x=-5 +162/53

5x= -265+162/53

5x=103/53

x=103/265

7 0
3 years ago
The school store opened on the first day of school with 45 notebooks and 15 pencils. Within two days it sold all of these items.
malfutka [58]

The number of pencils sold on the first day  is 5 pencils.

The number of notebooks sold on the first day  is 10 notebooks.

The number of pencils sold on the second day 10 pencils.

The number of notebooks sold on the second day   35 notebooks.

<u>Step-by-step explanation:</u>

Given data,

  • The total number of notebooks in the store = 45 notebooks.
  • The total number of Pencils in the store = 15 pencils.
  • The number of days that all items were sold = 2 days.

Now, you have to calculate the no.of notebooks and no. of pencils sold each day.

<u>In the first day :</u>

The number of sale of notebooks and pencils are given by,

Twice as many notebooks were sold as pencils.

Let us take, the number of pencils sold on the first day  = x

And,  the number of notebooks sold on the first day  = 2x (Twice as pencils).

<u>In the second day :</u>

The number of sale of notebooks and pencils are given by,

For every 7 notebooks​ sold, 2 pencils were sold.

The number of pencils sold on the second day =   2y

The number of notebooks sold on the second day   = 7y

<u> The equation is framed for number of notebooks sold on each day :</u>

The number of notebooks sold ⇒ 2x + 7y = 45   -------(1)

<u> The equation  is framed for number of pencils sold on each day :</u>

The number of pencils sold: x + 2y = 15  ----------(2)

Solving the equations by multiplying eq(2) by 2 and subtract it from eq(1),

  2x + 7y = 45

-<u> (2x + 4y) = 30</u>

   <u>        3y = 15  </u>

⇒ y = 15/3

⇒ y = 5

The value of y is 5.

Substitute y=5 in eq (2),

⇒ x + 2(5) = 15

⇒ x + 10 = 15

⇒ x = 15 - 10

⇒ x = 5

The value of x is 5.

First day sale,

The number of pencils sold on the first day  = x ⇒ 5 pencils

The number of notebooks sold on the first day  = 2x ⇒ 10 notebooks

Second day sale,

The number of pencils sold on the second day =   2y ⇒ 10 pencils

The number of notebooks sold on the second day   = 7y ⇒ 35 notebooks.

8 0
2 years ago
She is serving hot coffee and cold coffee in two rectangular-shaped tanks, each with dimensions width 8.75 inches, length 8.75 i
Blababa [14]

The volume of the coffee in each tank will be 1760. in³. The mass of cold coffee and hot coffee will be 6163.29 oz and 10213.45 oz. Then the number of the tank placed on a table is one only.

<h3>How to find the density and volume?</h3>

She is serving hot coffee and cold coffee in two rectangular-shaped tanks, each with dimensions width of 8.75 inches, a length of 8.75 inches, and a height of 23 inches.

The hot coffee has a density of 5.8 oz/in³ and the cold coffee has a density of 3.5 oz/ in³.

Then the volume of the coffee in each tank will be

We know that the dimension of both tanks is equal. Then the volume will remains equal.

Volume = L × B × H

Volume = 8.75 × 8.75 × 23

Volume = 1760.9375 ≅ 1760.94 in³

Then  the mass of the coffee in each the tank will be

The mass of hot coffee will be

Mass = Density × Volume

Mass = 5.8 × 1760.94

Mass = 10213.45 oz

The mass of cold coffee will be

Mass = Density × Volume

Mass = 3.5 × 1760.94

Mass = 6163.29 oz

Then the number of the tank placed on a table is one only.

More about the density and volume link is given below.

brainly.com/question/952755

#SPJ1

3 0
2 years ago
A spinner has red, green, blue and orange sections. The probability of landing on red is 2/3,on green 1/12, on blue is 1/12. Wha
lesya [120]

Answer: P(landing on orange)=1 - [2/3 + 1/12 + 1/12]

so <em><u>=1/6</u></em>

7 0
2 years ago
Find the length of the third side. If necessary, write in simplest radical form.
Arlecino [84]
Answer:

9

Explanation:

9 root 2 = root 81 x root 2 = root 162
Root 162 = 12.7279220614
9^2 + b^2 = 12.7279220614^2
81 + b^2 = 162
b^2 = 81
Root both
B = 9

4 0
2 years ago
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