Answer:
6,10,or 30 is your answer
<h2>
The area of a triangle is =54 square units</h2><h2>
The perpendicular distance from B to AC is = 
</h2>
Step-by-step explanation:
Given a triangle ABC with vertices A(2,1),B(12,2) and C(12,8)
The area of a triangle is= ![\frac{1}{2} [x_1(y_2-y_3) +x_2 (y_3- y_1)+x_3(y_1-y_2)]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%5Bx_1%28y_2-y_3%29%20%2Bx_2%20%28y_3-%20y_1%29%2Bx_3%28y_1-y_2%29%5D)
=![|\frac{1}{2} [2(2-8+12(8-1)+12(1-2)]|](https://tex.z-dn.net/?f=%7C%5Cfrac%7B1%7D%7B2%7D%20%5B2%282-8%2B12%288-1%29%2B12%281-2%29%5D%7C)
=
= 54 square units
The length of AC = 
= 
=
units
Let the perpendicular distance from B to AC be = x
According To Problem
⇔
units
Therefore the perpendicular distance from B to AC is =
Answer:
314 cm ^ 2
Step-by-step explanation:
First do, 3.14 x 20 ^ 2
3.14 x 20 ^ 2 = 1,256
Then do, 1,256/4
1,256/4 = 314
Why 4?
This part of the circle is 1/4 of the entire circle.
What does ^ mean?
It's just a way to say to the power of on a computer.
Hope this helps! :)
<h3>
Answer: 8p^3 + 10p^2 + 14p</h3>
Explanation:
The outer term 2p is distributed among the three terms inside the parenthesis. We will multiply 2p by each term inside
2p times 4p^2 = 2*4*p*p^2 = 8p^3
2p times 5p = 2*5*p*p = 10p^2
2p times 7 = 2*7p = 14p
The results 8p^3, 10p^2 and 14p are added up to get the final answer shown above. We do not have any like terms to combine, so we leave it as is.
