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3 years ago

Which is a physical property of milk

Chemistry

2 answers:

Crazy boy [7]3 years ago

6 0

Answer:

Physical Properties of Milk. Milk is a dilute emulsion consisting of an oil/fat dispersed phase and an aqueous colloidal continuous phase.

Explanation:

puteri [66]3 years ago

5 0

Answer:

The principal physical properties of milk include its density, redox properties, colligative properties, surface activity buffering capacity, rheological behaviour, conductivity, thermal properties and color.

Explanation:

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Calcium reacts with a polyatomic ion to form a compound with the general formula Ca(X). What would be the most likely formula fo

BartSMP [9]

Answer:

B) K2X

Explanation:

In an uncharged compound, the total oxidation state must be zero. The oxidation state of the calcium is +2, thus we get the following formula, where x is the oxidation state of the polyatomic ion X:

$x + 2 = 0 \\ x = 0 - 2 \\ x = - 2$

Also, it is known that potassium has an oxidation state of +1. Since the new compound also has a total oxidation state equal to zero, we get the following equation, where k is the number of K atoms:

$k \times 1 + ( - 2) = 0 \\ k - 2 = 0 \\ k = - ( - 2) \\ k = 2$

That's how it is found that the compumd consists of 2 K+ ions and one X ion.

6 0

3 years ago

Chromium is dissolved in sulfuric acid according to the following equation: Cr + H2SO4 ⇒ Cr2 (SO4) 3 + H2

Usimov [2.4K]

Answer:

$\large \boxed{\text{a)188.4 g; b) 98.67 $\, \%$}}$

Explanation:

We will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ: 98.08 392.18

2Cr + 3H₂SO₄ ⟶ Cr₂(SO₄)₃ + 3H₂

To solve the stoichiometry problem, you must

Use the molar mass of H₂SO₄ to convert the mass of H₂SO₄ to moles of H₂SO₄
Use the molar ratio to convert moles of H₂SO₄ to moles of Cr₂(SO₄)₃
Use the molar mass of Cr₂(SO₄)₃ to convert moles of Cr₂(SO₄)₃ to mass of Cr₂(SO₄)₃

a) Mass of Cr₂(SO₄)₃

(i) Mass of pure H₂SO₄

$\text{Mass of pure} = \text{165 g impure} \times \dfrac{\text{85.67 g pure} }{\text{100 g impure}} = \text{141.36 g pure}$

(ii) Moles of H₂SO₄

$\text{Moles of H$_{2}$SO}_{4} = \text{141.36 g H$_{2}$SO}_{4} \times \dfrac{\text{1 mol H$_{2}$SO}_{4}}{\text{98.08 g H$_{2}$SO}_{4}} = \text{1.441 mol H$_{2}$SO}_{4}$

(iii) Moles of Cr₂(SO₄)₃

The molar ratio is 1 mol Cr₂(SO₄)₃:3 mol H₂SO₄ $\text{Moles of Cr$_{2}$(SO$_{4}$)}_{3} = \text{1.441 mol H$_{2}$SO}_{4} \times \dfrac{\text{1 mol Cr$_{2}$(SO$_{4}$)}_{3}}{\text{3 mol H$_{2}$SO}_{4}} = \text{0.4804 mol Cr$_{2}$(SO$_{4}$)}_{3}$

(iv) Mass of Cr₂(SO₄)₃ $\text{Mass of Cr$_{2}$(SO$_{4}$)}_{3} = \text{0.4804 mol Cr$_{2}$(SO$_{4}$)}_{3} \times \dfrac{\text{392.18 g Cr$_{2}$(SO$_{4}$)}_{3}}{\text{1 mol Cr$_{2}$(SO$_{4}$)}_{3}} = \textbf{188.4 g Cr$_{2}$(SO$_{4}$)}_{3}\\\text{The mass of Cr$_{2}$(SO$_{4}$)$_{3}$ formed is $\large \boxed{\textbf{188.4 g}}$}$

b) Percentage yield

It is impossible to get a yield of 485.9 g. I will assume you meant 185.9 g.

$\text{Percentage yield} = \dfrac{\text{Actual yield}}{\text{Theoretical yield}} \times 100 \, \% = \dfrac{\text{185.9 g}}{\text{188.4 g}} \times 100 \, \% = \mathbf{98.67 \, \%}\\\\\text{The percentage yield is $\large \boxed{\mathbf{98.67 \, \%}}$}$

7 0

4 years ago

1. Which is an example of pure chemistry? testing the effects of lower concentrations of a drug on humans developing a cure for

motikmotik

Answer:

studying chemicals containing carbon.

Explanation:

Pure chemistry can be regarded as

branch of science that's based on conduction of basic research so that

personal knowledge can be acquired. It can be reffered to as theoretical branch of chemistry, not applied branch. It comes with curiosity about something, how and why it happens. For instance, studying chemicals containing carbon is to gain knowledge there's no applied chemistry here

7 0

3 years ago

The mass of an atom is equal to the number of

Solnce55 [7]

Explanation:

proton number and neutron number sums up to form the mass number

5 0

3 years ago

Read 2 more answers

How many moles of lithium chloride will be formed by the reaction of chloride with 4.28 mol of lithium bromide in the following

lys-0071 [83]

Answer:

The answer is 4.28 moles

Explanation:

This is super easy okay, you won't forget this!

Basically mole ratios, we're just looking at the coefficients in front of the compounds, multiplying them, and dividing them as we see fit.

In this example, you can see how you need 2 moles of lithium bromide (LiBr) for the reaction, and 2 moles of lithium chloride (LiCl) will be produced.

Basically, the <u>molar ratio</u> is when you divide numbers and see how much of this do I have for that (if that makes sense).

So if you were to divide the 2 moles of LiBr / 2 moles of LiCl = 1. So we know that the mole ratio for LiBr to LiCl is 1:1 or 2:2, either or, it's the same thing.

SO THE BIG IDEA, if we have 4.28 moles of lithium bromide reacting, we should also have 4.28 moles of lithium chloride produced, BECAUSE the <u>mole ratio</u> is 1:1.

I hope this makes sense please tell me if it doesn't, I will try my best to explain a little more.

7 0

3 years ago