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viva [34]
3 years ago
13

Chlorine has 17 valence electrons. true or false?

Chemistry
2 answers:
Nastasia [14]3 years ago
4 0
The answer is true .
OLga [1]3 years ago
3 0

chlorine only has 7 valance electrons!!!

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Charlotte is driving at 58.6 mi/h and receives a text message. She looks down at her phone and takes her eyes off the road for 4
kramer

Answer:   19.71 feet

Explanation:

Given:  Speed of Charlotte =58.6 mi/h

Since 1 hour = 3600 seconds

and 1 mile = 5280 feet

So, Speed of Charlotte = \dfrac{58.6\times5280}{3600}\approx85.95 mi/ sec

She looks down at her phone and takes her eyes off the road for 4.36 s.

Since , Distance = \dfrac{speed}{time}

So, Distance = \dfrac{85.95}{4.36}=19.71\ feet

Hence, Charlotte traveled  19.71 feet during this time.

8 0
3 years ago
Aluminum reacts with chlorine gas according to the following equation shown below. How many
sladkih [1.3K]

Answer:

nCl= 0,062x3/2=0,093(mol)

Explanation:

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2 years ago
All atoms of an element have the same number of ________. electrons neutrons protons protons plus neutrons
Cloud [144]

Answer:

protons

Explanation:

An element, by definition, always has the same number of protons.  Sodium, element 11, has 11 protons.  Anything with 11 protons is a sodium atom, regardless of the number of neutrons, electrons, or politicians.  

6 0
2 years ago
All of the factors described below could account for the difference in the sizes of the tomatoes. Which describes a way in which
disa [49]

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3 years ago
Nitric monoxide (NO) reacts with oxygen gas to form nitrogen dioxide (NO₂), a dark brown gas. If 5.895 mol of NO is mixed with 2
Schach [20]

Answer:

Limiting reactant: O2

grams NO2 produced = 230.276 g NO2

grams of NO unused = 26.67 gNO

Explanation:

2NO + O2 --> 2NO2

Step 1: Determine the molar ratio NO:O2

molar ratio NO:O2 = 5.895: 2.503 = 2.35

stoichiometric molar ratio NO:O2 = 2:1

So, O2 is the limiting reactant.

Step2: Determine the grams of NO2:

?g NO2 = moles O2 x (2moles NO2/1 mol O2) x (MM NO2/ 1 mol NO2) = 2.503 x 2 x 46 = 230.276 g NO2

Step 3: Determine the amount of excess reagent unreacted

moles excess NO reacted = moles O2 x (2 moles NO/1 mol O2) = 2.503 x 2 = 5.006 moles NO reacted

moles NO unreacted = total moles NO - moles NO reacted = 5.895-5.006 =0.889 moles NO unreacted

mass NO unreacted = moles NO unreacted x MM NO = 0.889 x 30 =26.67 g NO unreacted

8 0
3 years ago
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