Answer:
6.86 * 10^8 m
Explanation:
Parameters given:
Mass of hot gas, m = 2 kg
Gravitational Force, F = 618.2 N
Mass of Alpha Centauri, M = 2.178 * 10^30 kg
The gravitational force between two masses (the hot gas and Alpha Centauri) , m and M, at a distance, r, given as:
F = (G*M*m) / r²
Where G = gravitational constant
Therefore,
618.2 = (6.67 * 10^(-11) * 2.178 * 10^30 * 2) / r²
=> r² = (6.67 * 10^(-11) * 2.178 * 10^30 * 2) / 618.2
r² = 4.699 * 10^17 m²
=> r = 6.86 * 10^8 m
We are told that the hot gas is on the surface of Alpha Centauri, hence, the distance between both their centers is the radius of Alpha Centauri.
The mean radius of Alpha Centauri is 6.86 * 10^8 m.
Answer: barometer.
A cyclone is a storm or system of winds that rotates around a center of low atmospheric pressure. An anticyclone is a system of winds that rotates around a center of high atmospheric pressure.
There is no diagram below so I can't answer the question
(a) The kinetic energy of the projectile when it reaches the highest point in its trajectory is 900 J.
(b) The work done in firing the projectile is 2,500 J.
<h3>
Kinetic energy of the projectile at maximum height</h3>
The kinetic energy of the projectile when it reaches the highest point in its trajectory is calculated as follows;
K.E = ¹/₂mv₀ₓ²
where;
- m is mass of the projectile
- v₀ₓ is the initial horizontal component of the velocity at maximum height
<u>Note:</u> At maximum height the final vertical velocity is zero and the final horizontal velocity is equal to the initial horizontal velocity.
K.E = (0.5)(2)(30²)
K.E = 900 J
<h3>Work done in firing the projectile</h3>
Based on the principle of conservation of energy, the work done in firing the projectile is equal to the initial kinetic energy of the projectile.
W = K.E(i) = ¹/₂mv²
where;
- v is the resultant velocity
v = √(30² + 40²)
v = 50 m/s
W = (0.5)(2)(50²)
W = 2,500 J
Thus, the kinetic energy of the projectile when it reaches the highest point in its trajectory is 900 J.
The work done in firing the projectile is 2,500 J.
Learn more about kinetic energy here: brainly.com/question/25959744
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