Answer:
103.57 Km/h
Explanation:
From the question given above, the following data were obtained:
Distance = 725 Km
Time = 7 hours
Speed =?
Speed can be defined as the distance travelled per unit time. Mathematically, it is expressed as:
Speed = Distance /time
With the above formula, we can calculate how fast he will drive (i.e the speed) in order to get there on time. This is illustrated below:
Distance = 725 Km
Time = 7 hours
Speed =?
Speed = Distance /time
Speed = 725 / 7
Speed = 103.57 Km/h
Thus, to get there on time, he will drive with a speed of 103.57 Km/h
Answer:
There would be more hours of sunlight at the equator
The gravitational attractions are greatest be when the objects have large masses and they're closer together. Their sizes don't matter.
Answer:
the instantaneous velocity is 51 m/s
Explanation:
Given;
acceleration, a = 2 + 5t²
Acceleration is the change in velocity with time.
![a = \frac{dv}{dt} \\\\a = 2 + 5t^2\\\\The \ acceleration \ (a) \ is \ given \ so \ we \ have \ to \ find \ the \ velocity \ (v)\\\\To \ find \ the \ velocity, \ integrate\ both \ sides \ of \ the \ equation\\\\2 + 5t^2 = \frac{dv}{dt} \\\\\int\limits^3_0 {(2 + 5t^2)} \, dt = dv\\\\v = [2t + \frac{5t^3}{3} ]^3_0\\\\v = 2(3) + \frac{5(3)^3}{3} \\\\v = 6 + 5(3)^2\\\\v = 6 + 45\\\\v = 51 \ m/s](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7Bdv%7D%7Bdt%7D%20%5C%5C%5C%5Ca%20%3D%202%20%2B%205t%5E2%5C%5C%5C%5CThe%20%5C%20acceleration%20%5C%20%28a%29%20%5C%20is%20%5C%20given%20%5C%20so%20%5C%20we%20%5C%20have%20%5C%20to%20%5C%20find%20%5C%20the%20%5C%20velocity%20%5C%20%28v%29%5C%5C%5C%5CTo%20%5C%20find%20%5C%20the%20%5C%20velocity%2C%20%5C%20integrate%5C%20both%20%5C%20sides%20%5C%20of%20%5C%20the%20%5C%20equation%5C%5C%5C%5C2%20%2B%205t%5E2%20%3D%20%5Cfrac%7Bdv%7D%7Bdt%7D%20%5C%5C%5C%5C%5Cint%5Climits%5E3_0%20%7B%282%20%2B%205t%5E2%29%7D%20%5C%2C%20dt%20%3D%20dv%5C%5C%5C%5Cv%20%3D%20%5B2t%20%2B%20%5Cfrac%7B5t%5E3%7D%7B3%7D%20%5D%5E3_0%5C%5C%5C%5Cv%20%3D%202%283%29%20%2B%20%5Cfrac%7B5%283%29%5E3%7D%7B3%7D%20%5C%5C%5C%5Cv%20%3D%206%20%2B%205%283%29%5E2%5C%5C%5C%5Cv%20%3D%206%20%2B%2045%5C%5C%5C%5Cv%20%3D%2051%20%5C%20m%2Fs)
Therefore, the instantaneous velocity is 51 m/s
Ticker Tape analysis is a common way of analyzing the motion of the objects to perform in the physics laboratory. A long tape is attached to a moving object and threaded through a device that places a tick upon the tape at regular intervals of time. This ticker tape can also determine if the object is fast or slow. It can also reveal if the object is moving with a constant velocity or accelerating. The changing velocity and acceleration represented by the changing distance between dots in the ticker tape. And also the constant velocity and therefore no acceleration represent the constant distance between dots.