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IgorLugansk [536]
3 years ago
5

Which instrument produces the sound of a single frequency?

Physics
1 answer:
notka56 [123]3 years ago
6 0
NO musical instrument produces a 'pure' tone with only a
single frequency in it.

EVERY instrument produces more or less harmonics (multiples)
in addition to the basic frequency it's playing.

The percussion instruments (drums etc) are the richest producers
of bunches of different frequencies.

Fuzzy electric guitars are next richest.

The strings and brass instruments are moderate producers of
harmonics ... I can't remember which is greater than the other.

Then come the woodwinds ... clarinet, oboe, etc.

The closest to 'pure' tones of single frequency are the sounds
made by the flute and piccolo, but even these are far from 'pure'.

The only way to get a true single-frequency sound is from an
electronic 'sine wave' generator.
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A boy throws a baseball onto a roof and it rolls back down and off the roof with a speed of 3.05 m/s. If the roof is pitched at
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1) Time in the air: 0.78 s

The motion of the ball is a projectile motion, which consists of two independent motions:

- A horizontal motion with constant horizontal velocity

- A vertical motion with constant downward acceleration of

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The initial vertical velocity is

u_y = u sin \theta = (3.05)(sin(-40^{\circ}))=-1.96 m/s

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The vertical position of the ball is given by

y(t) = h + u_y t + \frac{1}{2}gt^2

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0 = 4.50 -1.96t-4.9t^2

This is a second-order equation; solving for t, we get

t = -1.18 s

t = 0.78 s

We discard the negative solution since it has no physical meaning, so we can say that the ball spent 0.78 s in the air.

2) Horizontal distance: 1.83 m

For this second part of the problem, we just have to consider the horizontal motion of the ball.

As we said previously, the motion of the ball along the horizontal direction is a uniform motion with constant velocity, which is given by

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where u = 3.05 m/s is the initial speed and \theta the angle of projection.

For a uniform motion, we can use the following relationship between distance covered and velocity:

d=v_x t

and substituting t = 0.78 s, we find the total distance travelled along the horizontal direction by the ball before reaching the ground:

d=(2.34)(0.78)=1.83 m

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