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2 years ago

The thermal energy of what system does change

Physics

1 answer:

Inessa05 [86]2 years ago

4 0

Answer:

there is the increase the temperature of cold body and decrease the temperature of hot body

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3. Calculate the wavelength of wave that has a frequency of 4.75 x 1012Hz.

Klio2033 [76]

Frequency=v=4.75×10^12Hz
Wavelength=?

We know

$\boxed{\sf \lambda=\dfrac{C}{V}}$

$\\ \sf\longmapsto \lambda=\dfrac{3\times 10^8ms^{-1}}{4.75\times 10^{12}s^{-1}}$

$\\ \sf\longmapsto \lambda=0.631\times 10^{-4}m$

$\\ \sf\longmapsto \lambda=6.31\times 10^{-5}m$

4 0

2 years ago

he capacitor can withstand a peak voltage of 550 VV . If the voltage source operates at the resonance frequency, what maximum vo

anygoal [31]

Answer:

The maximum voltage is 39.08 V.

Explanation:

Given that,

Voltage = 550 V

Suppose, In an L-R-C series circuit, the resistance is 400 ohms, the inductance is 0.380 Henry, and the capacitance is $1.20\times10^{-2}\mu F$

We need to calculate the resonant frequency

Using formula of resonant frequency

$f=\dfrac{1}{2\pi\sqrt{LC}}$

Put the value into the formula

$f=\dfrac{1}{2\pi\sqrt{0.380\times1.20\times10^{-8}}}$

$f=2356.8\ Hz$

We need to calculate the maximum current

Using formula of current

$I=\dfrac{V_{c}}{X_{c}}$

$I=2\pi f C\times V_{c}$

Put the value into the formula

$I=2\pi\times2356.8\times1.20\times10^{-8}\times550$

$I=0.0977\ A$

We need to calculate the impedance of the circuit

Using formula of impedance

$Z=\sqrt{R^2+(X_{L}-X_{C})^2}$

At resonant frequency , $X_{L}=X_{C}$

So, Z = R

We need to calculate the maximum voltage

Using formula of voltage

$V=IR$

Put the value into the formula

$V=0.0977\times400$

$V=39.08\ V$

Hence, The maximum voltage is 39.08 V.

4 0

3 years ago

Please solce thiss quesstion

noname [10]

Answer:

Can you give a clearer question

Explanation:

pls give me points i have questions

4 0

3 years ago

The most distal part of a nail is called the ____________ . The most proximal part of the nail that is embedded in the skin is t

ankoles [38]

Answer:

1.Free edge

2.Nail Root

3.Nail matrix

4.lunula

Note: The numbering coincides respectively with the dashes in the questions.

Explanation:

Free edge is the distal white nail ending.

Nail Root is the proximal part of the nail embedded in the skin.

Nail matrix is the actively growing part of the nail were the nail root thickens

Lunula the whitish semilunar area of the proximal end of the nail body it appears whitish because stratum basala obscures. the underlying blood vessels.

7 0

3 years ago

The cable of a crane is lifting a 750 kg girder. The girder increases its speed from 0.25 m/s to 0.75 m/s in a distance of 3.5 m

IgorC [24]

To solve this exercise it is necessary to apply the equations concerning Work, both by general definition and by conservation of energy.

In other words, the work done by an object due to gravity is the equivalent to that defined by the potential energy equations, that is

$W= mg\Delta h$

Where,

m=mass

g=gravitational acceleration

$\Delta h =$ Change in height

On the other hand we have that the work done by tension is defined by the conservation of kinetic and potential energy, that is to say

$W= \Delta KE + \Delta PE$

Where,

$\Delta KE =$ Change in Kinetic Energy

$\Delta PE =$ Change in Potential Energy

PART A) As defined by the work done by gravity would be given by,

$W = mg\Delta h$

$W = (750)(9.8)(3.5)$

$W = 25.725kJ$

Therefore the work done by gravity is 25.725kJ

PART B) The work done by the tension applies the energy conservation equation, that is to say

$W= \Delta KE + \Delta PE$

$W = (\frac{1}{2}mv_f^2-\frac{1}{2}mv_i^2)+(mgh_f-mgh_i)$

$W = \frac{1}{2}m(v_f^2-v_i^2)+mg(h_f-h_i)$

Replacing with our values,

$W = \frac{1}{2}(750)(0.75^2-0.25^2)+(750)(9.8)(3.5)$

$W = 25.912kJ$

Therefore the work done by tension is 25.9kJ

5 0

3 years ago