Answer:
c
Step-by-step explanation:
<span>Orthocenter is at (-3,3)
The orthocenter of a triangle is the intersection of the three heights of the triangle (a line passing through a vertex of the triangle that's perpendicular to the opposite side from the vertex. Those 3 lines should intersect at the same point and that point may be either inside or outside of the triangle. So, let's calculate the 3 lines (we could get by with just 2 of them, but the 3rd line acts as a nice cross check to make certain we didn't do any mistakes.)
Slope XY = (3 - 3)/(-3 - 1) = 0/-4 = 0
Ick. XY is a completely horizontal line and it's perpendicular will be a complete vertical line with a slope of infinity. But that's enough to tell us that the orthocenter will have the same x-coordinate value as vertex Z which is -3.
Slope XZ = (3 - 0)/(-3 - (-3)) = 3/0
Another ick. This slope is completely vertical. So the perpendicular will be complete horizontal with a slope of 0 and will have the same y-coordinate value as vertex Y which is 3.
So the orthocenter is at (-3,3).</span>
a) CE = 16 ft
b) BC = 6√2 ft [ BY Pythagoras theorem]
c) m angle CFD = 90°
d) m angle DBE = 90°
Y=mx+b
Y=x+15000 OR Y=1x+15000
I hope that helped
Answer:
<h3>19,133.067</h3>
Step-by-step explanation:
Volume of the ball (spherical in nature) Vb = 4/3πrb³
Volume of the hole Vh = 4/3πrh³
rb is the radius of the ball
rh is the radius of the hole
If a ball of radius 17 has a round hole of radius 7 drilled through its center, the volume of the resulting solid will be expressed as:
V = Vb - Vh
V = 4/3πrb³ - 4/3πrh³
factor out the like terms;
V = 4/3π(rb³-rh³)
Given
rb = 17
rh = 7
V = 4/3π(17³-7³)
V = 4/3π(4913-343)
V = 4/3π(4570)
V = (4π*4570)/3
V = 57,399.2/3
V = 19,133.067
Hence the volume of the resulting solid is 19,133.067
