Answer:
Both the values fall in the critical region so we reject H0: p ≤ 0.01 and conclude that the results are significantly different from chance identification and it is not a sample fluctuation.
Step-by-step explanation:
1) Formulate the hypothesis
H0: p ≤ 0.01 against the claim Ha: p > 0.01
2) Choose the significance level ∝= 0.01
3) The test statistics under H0 is
z= x -np /√npq ( without continuity correction)
z= x ± 1/2 -np /√npq ( with continuity correction)
4) the critical region is z> ±2.33 because the alternate hypothesis is stated on greater than basis.
5)Computations:
Z= x -np /√npq ( without continuity correction)
Z= 6- 600( 0.03)/√ 600( 0.03)(0.97)
z= - 2.82 ( without continuity correction)
z= x ± 1/2 -np /√npq ( with continuity correction)
Z= (6-0.5)- 600( 0.03)/√ 600( 0.03)(0.97)
z= -12.5/4.1785
z= -0.29915 ( with continuity correction)
6) Both the values fall in the critical region so we reject H0: p ≤ 0.01 and conclude that the results are significantly different from chance identification and it is not a sample fluctuation.
