The answer is to 18/3-7+2 x 5 is 3
Answer:
B (I think)
Step-by-step explanation:
A function can't have two X values that are the same (If I remember correctly) and the second table is the only one that doesn't have duplicated X values
Answer:
The flagpole's shadow is 16.875 feet longer than the man's shadow
Step-by-step explanation:
The total length of the shadow is expressed by taking its actual length by a factor that depends on the position of the sun which is constant for the man too. The expression is as follows;
Height of the shadow=actual height of the flagpole×factor
where;
length of the flagpole's shadow=22.5 feet
actual height of the flagpole=32 feet
factor=f
replacing;
22.5=32×f
32 f=22.5
f=22.5/32
f=0.703125
Using this factor in the expression below;
Length of man's shadow=actual height of man×factor
where;
length of man's shadow=m
actual height of man=8 feet
factor=0.703125
replacing;
length of man's shadow=8×0.703125=5.625 feet
Determine how much longer the flagpole's shadow is as follows;
flagpoles shadow-man's shadow=22.5-5.625=16.875 feet
The flagpole's shadow is 16.875 feet longer than the man's shadow
Okay, so first you draw a picture and let x be the distance from point D to the rest stop. Then the distance from point to the rest stop is 8 - x
You know that the length of the new trail is y + z, where y is the distance from Ancaster to the rest stop and z is the distance from Dundas to the rest stop.
Now by the Pythagorean theorem, y^2 = 4^2 + x^2 and z^2 = 6^2 + (8 - x) ^2
So take square roots of these, add them, and minimize.
Note: I am assuming the path is perfectly straight, otherwise this approach fails.
