The distance from Humood's house to the school is 500m
<h3>How to determine the distance from Humood's house to the school?</h3>
The given parameters are:
Humood's house is (-5,7)
The school is (3,1)
The distance between both points is calculated using

Substitute the known values in the above equation

Evaluate
d = 10
Each unit in the graph is 50m.
So, we have
Distance =10 * 50m
Evaluate the product
Distance = 500m
Hence, the distance from Humood's house to the school is 500m
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Answer:
Step-by-step explanation:
y-5=3(x+2)
y-5=3x+6
y-5-6=3x+6-6
y-1=3x
The absolute minimum of this graph is y=-10
You have to multiply 36 times 4 =144 . So you do this like this (30 times 4) +(4 times 6)= so (120)+(24)= 144. Answer is 144