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3 years ago

Name the intersection of plane bpq and plane cpq. 1) the planes do not intersect. 2) bp 3)pq 4)cq

1 answer:

6 0

Imagine two planes: they can be parallel or not. If they are parallel, then they don't have common points, but your planes have common points P and Q.

So, you can conclude that these two planes are not parallel, then they should intersect. Two planes intersect <span>in a straight line and this line consists of all common points of both planes.
</span>
If planes are named BPQ (points B, P, Q do not lie on one straight line) and CPQ (points C, P, Q do not lie on one straight line), you can see two common points P and Q. Hence the intersection line must contain these two points and may be named as PQ (and points B and C do not lie on this line).

Answer: correct choice is C.

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3 years ago

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Zinaida [17]

Answer:

I just learned this about a few weeks ago I hope this helps.

Step-by-step explanation:

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2 years ago

In a lab, a scientist is growing bacteria for a study. The scientist begins with a bacteria

Diano4ka-milaya [45]

Answer:

The answer is below

Step-by-step explanation:

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$P(t)=ae^{rt}\\\\where\ t\ is\ the\ number\ of \ hours, P(t)\ is\ the \ population\ at\ t\ hours\\\and\ a=population\ at\ start$

At 2 hours, the population is 62 cells, hence:

$P(2)=ae^{2r}\\\\62=ae^{2r}\ \ .\ \ .\ \ .\ (1)$

After another 2 hours (4 hours), the population is 1 million:

$P(4)=ae^{4r}\\\\1000000=ae^{4r}\ \ .\ \ .\ \ .\ (2)\\\\Divide \ equation\ 2\ by\ equation\ 1:\\\\\frac{1000000}{62}=\frac{ae^{4r}}{ae^{2r}} \\\\16129=e^{2r}\\\\ln(e^{2r})=ln(16129)\\\\2r=9.688\\\\r=4.844$

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4 0

3 years ago

Send help 15 and 16 pls

lara [203]

Step-by-step explanation:

15. If f(x) = 20x, adding a $10 fee for cleaning would be

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The graph of g(x) is shifted 10 units up from the graph of f(x).

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g(x) shifted f(x) 5 units to the right.

h(x) is 3 times steeper than f(x).

If this is the correct answer, then please give it the brainliest.

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3 years ago