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3 years ago

Name the intersection of plane bpq and plane cpq. 1) the planes do not intersect. 2) bp 3)pq 4)cq

1 answer:

6 0

Imagine two planes: they can be parallel or not. If they are parallel, then they don't have common points, but your planes have common points P and Q.

So, you can conclude that these two planes are not parallel, then they should intersect. Two planes intersect in a straight line and this line consists of all common points of both planes.

If planes are named BPQ (points B, P, Q do not lie on one straight line) and CPQ (points C, P, Q do not lie on one straight line), you can see two common points P and Q. Hence the intersection line must contain these two points and may be named as PQ (and points B and C do not lie on this line).

Answer: correct choice is C.

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State the equation of the following graphs. Someone please help ASAP

Vaselesa [24]

Answer

y = 1(x +1) - 3

Explanation

A quadratic equation of the form y = ax^2 + bx + c

This written in complete the square form provides you with the vertex (either a maximum or minimum point depending on the equation).

This results in y = a(x + p) + q

Where - p is the x value and q is the y value of turning point.

For graph 22, x = -1 and y = -3

Therefore, the equation is of the form

y = a(x + 1) - 3 (*)

We still need the value a, this can be obtained by using the y-intercept we are given.

We are told x = 0 when y = -2

Substitute this in (*) equation:

-2 = a(0+1) - 3

-2 = a - 3

a = 1

Therefore final equation is

y = 1(x +1) - 3

This should provide you with the train of thought of how the second question should also be tackled.

If unsure about why the equation
y = a(x + p) + q gives the vertex ask in comments I will respond

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3 years ago

Is quotient subtract or divide?

iogann1982 [59]

Answer:

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Kiesha and her classmates wrote proportions for the reduction of a triangle. A larger and smaller triangle have corresponding he

MrMuchimi

Answer:

the 2nd one

Step-by-step explanation:

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Find the work done when a crane lifts a -pound boulder through a vertical distance of feet. Round to the nearest foot-pound.

goldenfox [79]

Answer:

72000ft-1b

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3 years ago

What is the solution set for 2x+5y>-1 and 4x-3<-3?

bekas [8.4K]

PROBLEM ONE

•

Solving for x in 2x + 5y > -1.

•

Step 1 ) Subtract 5y from both sides.

2x + 5y > -1

2x + 5y - 5y > -1 - 5y

2x > -1 - 5y

Step 2 ) Divide both sides by 2.

2x > -1 - 5y

$\displaystyle\frac{2x}{2} > \displaystyle\frac{-1 - 5y}{2}$

$\displaystyle\ x > \frac{-1 - 5y}{2}$

So, the solution for x in 2x + 5y > -1 is...

$\displaystyle\ x > \frac{-1 - 5y}{2}$

•

Solving for y in 2x + 5y > -1.

•

Step 1 ) Subtract 2x from both sides.

2x + 5y > -1

2x - 2x + 5y > -1 - 2x

5y > -1 - 1x

Step 2 ) Divide both sides by 5.

5y > -1 - 1x

$\displaystyle\frac{5x}{5} > \frac{-1 -1x}{5}$

$\displaystyle\ x > \frac{-1 -1x}{5}$

So, the solution for y in 2x + 5y > -1 is...

$\displaystyle\ x > \frac{-1 -1x}{5}$

•

PROBLEM TWO

•

Solving for x in 4x - 3 < -3.

•

Step 1 ) Subtract 3 from both sides.

4x - 3 < -3

4x -3 - 3 < -3 - 3

4x < 0

Step 2 ) Divide both sides by x.

4x < 0

$\displaystyle\frac{4x}{4}$

x < 0

So, the solution for x in 4x - 3 < -3 is...

x < 0

•

- Marlon Nunez

7 0

3 years ago