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3 years ago

Name the intersection of plane bpq and plane cpq. 1) the planes do not intersect. 2) bp 3)pq 4)cq

1 answer:

6 0

Imagine two planes: they can be parallel or not. If they are parallel, then they don't have common points, but your planes have common points P and Q.

So, you can conclude that these two planes are not parallel, then they should intersect. Two planes intersect <span>in a straight line and this line consists of all common points of both planes.
</span>
If planes are named BPQ (points B, P, Q do not lie on one straight line) and CPQ (points C, P, Q do not lie on one straight line), you can see two common points P and Q. Hence the intersection line must contain these two points and may be named as PQ (and points B and C do not lie on this line).

Answer: correct choice is C.

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The height of each story of an office building is 9 3/4 feet. The height is measured from the ceiling to the floor. The building

lesya692 [45]

Answer:

The correct answer is A) -19 1/2

Step-by-step explanation:

3 0

3 years ago

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Which number produces an irrational number when multiplied by 1/3

MArishka [77]

We can simply observe that.

0.777... is rational, because it is a number with infinite but repeating decimal part.
1/3 is rational, because it's the division between two integers
$-\sqrt{16}=-4$ , so this is rational as well.

Since the product of two rational numbers is always rational, we have that

$0.\bar{7}\cdot \dfrac{1}{3},\quad \dfrac{1}{3}\cdot \dfrac{1}{3},\quad -4\cdot \dfrac{1}{3}$

are all rationals, since they are the product of two rationals.

On the other hand, we have

$\sqrt{27}=\sqrt{9\cdot 3}=3\sqrt{3}$

and thus

$3\sqrt{3}\cdot \dfrac{1}{3}=\sqrt{3}$

which is irrational.

3 0

3 years ago

Objects A and B are in harmonic motion modeled by

Zepler [3.9K]

Answer:

The phase difference between yA and yB is $\frac{-\pi }{12}$

Step-by-step explanation:

Given harmonic modeled as :

yA = 8 sin(2t - $\frac{\pi }{3}$ ) And

yB = 8 sin(2t - $\frac{\pi }{4}$ )

The function as written as :

y = a sin(ωt - Ф) where Ф is phase difference

So , phase difference between yA and yB = ( Ф_1 - Ф_2 )

Or phase difference between yA and yB = ( - $\frac{\pi }{3}$ + $\frac{\pi }{4}$ )

Or, phase difference between yA and yB = $(\frac{-4\pi +3\pi }{12})$

I.e phase difference between yA and yB = $\frac{-\pi }{12}$

Hence The phase difference between yA and yB is $\frac{-\pi }{12}$ Answer

4 0

4 years ago

Read 2 more answers

You spend $20 total on tubes of paint and disposable brushes for an art project. Tubes of paint cost $4.00 each and paintbrushes

hram777 [196]

You are buying 2 items so let's use two different variables to represent each:
p = number of tubes of paint
b = number of disposable brushes
cost = price per item × number of items
Equations from information given:
4p + 0.50b = 20 ← from the first 2 sentences
2p = b ← if there are twice as many brushes as paint tubes you need 2 times paint tubes to equal number of brushes
Solve the problem by using substitution... 1b equals 2p so replace b with that:
4p + 0.50(2p) = 20
4p + 1p = 20 ← 0.50 is half so half of 2p is 1p
5p = 20 ← combine like terms
p = 4 ← divide both sides of the equation by 5
Recall the equation 2p = b replace p with 4
2(4) = b
8 = b
ANSWER:
You purchased 4 tubes of paint and 8 disposable brushes.

8 0

3 years ago

Graph the equation in a coordinate plane, x+2y=4

natta225 [31]

Hope this helps!

Stay safe, have a good day :D

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4 years ago