To find the maximum velocity you have to differentiate the function respect to r.
v = k(R - r)r^2 = kRr^2 - krr^2 = kRr^2 - kr^3
k and R are constants.
=> v' = 2kRr - 3kr^2 = kr(2R - 3r)
maximum velocity => v' = 0 => kr(2R - 3r) = 0
r = 0 or 2R - 3r = 0 => r = 2R / 3
Answer: r = 2R / 3
To answer this item, we use dimensional analysis and conversion factor, 1 revolution is equal to 2π rad. Using the concept and the given,
n = (14.2 revolutions / 8 seconds)(2π rad/1 rev)
n = 11.15 rad/s
Thus, the angular velocity is equal to 11.15 rad/s.
<span>Its going to be the part that has a 90 degree angle so half of the square in the corner.
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The horizontal distance between the base of the ladder and the wall is: 11.8 foot