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4 years ago

An acidic solution at 25°c will have a hydronium ion concentration and a ph value .

Chemistry

1 answer:

lesantik [10]4 years ago

3 0

The given question is incomplete. The complete question is:

An acidic solution at 25°C will have a hydronium ion concentration ________ and a pH value ________.

$[H_3O^+]$ > $1\times 10^{-7}$ M, pH < 7.00

$[H_3O^+]$ < $1\times 10^{-7}$ , pH < 7.00

$[H_3O^+]$ < $1\times 10^{-7}$ ,, pH > 7.00

$[H_3O^+]$ > $1\times 10^{-7}$ ,, pH > 7.00

Answer: $[H_3O^+]$ > $1\times 10^{-7}$ M, pH < 7.00

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

Acids have pH ranging from 1 to 6.9, bases have pH ranging from 7.1 to 14 and neutral solutions have pH equal to 7.

$pH=-\log [H_3O^+]$

$7=-log[H_3O^+]$

$[H_3O^+]=10^{-7}$

As pH of acids is less than 7, the hydronium ion concentration is greater than

Thus the correct option is $[H_3O^+]$ > $1\times 10^{-7}$ M, pH < 7.00

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Of the following gases, ________ will have the greatest rate of effusion at a given temperature. Of the following gases, _______

kolezko [41]

<u>Answer:</u> From the given gases, the greatest rate of effusion is of $CH_4$

<u>Explanation:</u>

Rate of effusion of a gas is determined by a law known as Graham's Law.

This law states that the rate of effusion or diffusion of a gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows:

$\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

It is visible that molar mass is inversely related to rate of effusion. So, the gas having lowest molar mass will have the highest rate of effusion.

For the given gases:

Molar mass of $NH_3=17g/mol$

Molar mass of $HCl=36.5g/mol$

Molar mass of $CH_4=16g/mol$

Molar mass of $Ar=40g/mol$

Molar mass of $HBr=81g/mol$

The molar mass of methane gas is the lowest. Thus, it will have the greatest rate of effusion.

Hence, the greatest rate of effusion is of $CH_4$

8 0

4 years ago

¿A qué grupo pertenecen los átomos de Z = 8, Z= 36 y Z=39? ¿Cuántas capas de electrones tiene cada uno? ¿Cuántos electrones harí

zaharov [31]

Answer:

Mira la explicación.

Explanation:

¡Hola!

En este caso, podemos encontrar facilmente el grupo al que pertenecen dichos elementos con números atómicos 8, 36 y 39 respectivamente mediante su búsqueda en la tabla periódica. Así, z=8 corresponde a oxígeno, z=36 a kriptón y z=39 a itrio.

Por otro lado, para saber el número de capas, debemos desarrollar la configuración electrónica para cada uno:

$O: 1s^2,2s^2,2p^4\\Kr: 1s^2,2s^2,2p^6,3s^2,3p^6,4s^2,3d^{10},4p^6\\Y:1s^2,2s^2,2p^6,3s^2,3p^6,4s^2,3d^{10},4p^6,5s^2,4d^1$

Con esto, vemos que oxígeno tiene dos capas, kripton cuatro capas e iritrio cinco, a lo que a oxígeno le faltan dos electrones para llenar dicha capa, a kripton ninguno y a iritrio nueve.

Saludos.

3 0

3 years ago

The actual density of pennies made before 1982 is about 8.8 g/mL. The actual density of pennies made after 1982 is about 7.2 g/m

trasher [3.6K]

To obtain more accurate values of the densities of the pennies:

more trials can be conducted to reduces the effect of measurement errors
more care should be taken in taken volume measurements by displacement of water to avoid splashing of water.

<h3>What is density of a substance?</h3>

The density of a substance is the ratio of the mass of the substance to the volume of that substance.

It is a measure of the compactness of the matter in a substance.

The densities of the pennies made before 1982 was 8.7 g/ml

The actual density of pennies made before 1982 is about 8.8 g/mL.

The densities of the pennies made after 1982 was 6.9 g/ml

The actual density of pennies made after 1982 is about 7.2 g/mL.

Due to several random and experimental errors, the values obtained from the experiment are not exactly the same with the accepted values.

To obtain more accurate values:

more trials can be conducted to reduces the effect of measurement errors
more care should be taken in taken volume measurements by displacement of water to avoid splashing of water.

In conclusion, the densities varied as as a result of random and experimental errors.

Learn more about density at: brainly.com/question/1354972

#SPJ1

7 0

2 years ago

How much time does it take for a truck to slow down if its acceleration is -15m/s2 and the change in velocity is -30m/s

damaskus [11]

Answer:

Explanation:

Given parameters:

Acceleration of the truck = 15m/s²

change in Velocity = 30m/s

Unknown:

Time taken for the body to slow down = ?

Solution:

Acceleration is the rate of change of velocity ;

Acceleration = $\frac{change in velocity}{time}$

time = $\frac{change in velocity }{acceleration}$

Now insert the parameters and solve;

time = $\frac{30}{15}$ = 2s

5 0

3 years ago

A sample of quartz, which has a specific heat capacity of , is dropped into an insulated container containing of water at and a

klasskru [66]

This question is incomplete, the complete question is;

A 17.0 g sample of quartz, which has a specific heat capacity of 0.730 J.g⁻¹°C⁻¹, is dropped into an insulated container containing 200.0 g of water at 85°C and a constant pressure of 1 atm . The initial temperature of the quartz is 7.2°C.

Assuming no heat is absorbed from or by the container, or the surroundings, calculate the equilibrium temperature of the water. Be sure your answer has the correct 3 number of significant digits.

Answer:

the equilibrium temperature of the water is 83.9°C

Explanation:

Given the data in the question;

Since no heat is absorbed from or by the container, or the surroundings;

Then Heat lost by the quartz = heat gained by water

ΔH1 = ΔH2

DH = mcΔT

where m is mass, C is specific heat capacity and ΔT is temperature change;

(mcΔT)1 = (mcΔT)2

we know that; specific heat capacity of is 4200 Joule/Kilogram K (J/kg∙K) = 4.2 (J/g∙°C)

we substitute

17.0g × 0.730 J.g⁻¹°C⁻¹ × ( 7.2°C - T2) = 200.0g × 4.2 J/g∙°C × ( T2 - 85°C)

89.352 - 12.41T2 = 840T2 - 71400

840T2 + 12.41T2 = 89.352 + 71400

852.41T2 = 71489.35

T2 = 71489.35 / 852.41 = 83.86°C ≈ 83.9°C

Therefore, the equilibrium temperature of the water is 83.9°C

3 0

3 years ago

An acidic solution at 25°c will have a hydronium ion concentration ________ and a ph value ________.

An acidic solution at 25°c will have a hydronium ion concentration and a ph value .