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Eva8 [605]
3 years ago
12

Phenolphthalein has a pka of 9.7 and is colorless in its acid form and pink in its basic form. part a for ph= 2.0 calculate [in−

]/[hin].
Chemistry
2 answers:
Tresset [83]3 years ago
8 0

Answer:

1.9953 × 10⁻⁸

Explanation:

Considering the Henderson- Hasselbalch equation for the calculation of the pH of the indicator as:

pH = pKa + log[In⁻]/[HIn]

Where Ka is the dissociation constant of the acid.

Given, pKa = 9.7

pH = 2.0

So,  

2.0 = 9.7 + log[In⁻]/[HIn]

log[In⁻]/[HIn]  = - 7.7

<u>[In⁻]/[HIn] = Antilog (-7.7) = 1.9953 × 10⁻⁸</u>

Karo-lina-s [1.5K]3 years ago
4 0
Use the h-h equation! 

pH = pKa + log[In-/HIn]
2.0 = 9.7 + log[In-/HIn]
-7.7 = log[In-/HIn]
10^-7.7 = [In-/HIn]
[In-/HIn] = 1.995 x 10^-8

Hope this helps!
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What is the volume of 58.0g of chlorine gas at stp
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At standard temperature and pressure, the volume of 58 gms of chlorine gas is 7.08 L.

<h3>What is STP?</h3>

STP is the condition of the ideal gas that relates to the moles, pressure, temperature, and volume. The ideal gas law at the STP is given as:

PV = nRT

Given at STP,

Pressure (P) = 1 atm

Temperature (T) = 273 K

Gas constant (R) = 0.0821 L atm/ mol K

Moles (n) of chlorine gas is calculated as:

Moles = Mass / Molar mass

n = 58.0 / 70.90

= 0.818 moles

The volume for the ideal gas equation is calculated as:

V = n * R * T / P

V = 7.08 / 1

V = 7.08 L

Therefore, at STP the volume of the gas is 7.08 L.

Learn more about STP here:

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5 0
2 years ago
12. How are secondary sources of energy different from other energy resources?
Mkey [24]

Answer:

A primary source of energy is a fossil fuel , nuclear fuel , wind or sunlight in an unconverted state . A secondary source of energy is created when a primary source of energy is burned or otherwise converted into a form , like electricity, that can be used for useful work.

Explanation:

5 0
3 years ago
A geologist discovers a fault in a massive rock while out in the field. He notices that the fault occurs at an angle and that th
Ludmilka [50]

Answer: normal fault

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On the basis of the above information, the normal fault is the fault that should be found by the geologists in the rock.

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3 years ago
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Calculate the wavelength, in nanometers, of the light emitted by a hydrogen atom when its electron fallsfrom the n = 7 to the n
Helga [31]

Answer:

λ=2167.6 nm

The wavelength of light emitted is 2167.6 nm.

Explanation:

We recall that Eₙ=\frac{-2.18*10^{-18} J}{n^{2} }

since there was transition from n7 to n=4 we will first calculate the change in the energy i.e ΔE

ΔE=E₄-E₇

ΔE=-2.18*10^{-18} J(\frac{1}{4^{2} } -\frac{1}{7^{2} } )

ΔE=-9.1760*10^-20 J

Now:

|ΔE|=Energy of photon=h*v=h*c/λ

λ=h*c/|ΔE|

λ=\frac{6.63*10^{-34}J.s*3.00*10^{8}m/s  }{9.1760*10^{-20} J }

λ=2.1676*10^-6 m

λ=2167.6*10^-9 m

λ=2167.6 nm

The wavelength of light emitted is 2167.6 nm.

5 0
3 years ago
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gregori [183]
True is the correct answer
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3 years ago
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