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nadya68 [22]
3 years ago
13

Which of the following statements is true concerning an aqueous solution of the weak base NH3?

Chemistry
1 answer:
babunello [35]3 years ago
8 0

Answer: Option (A) is the correct answer.

Explanation:

When weak base NH_{3} is dissolved in water then the reaction will be as follows.

       NH_{3} + H_{2}O \rightarrow NH^{+}_{4} + OH^{-}

When NH_{3} is compared with water then oxygen atom of H_{2}O being more electronegative in nature will keep its lone pair of electrons towards itself.

Hence, water will act as a neutral molecule and hence, NH_{3} will act as a stronger base as compared to H_{2}O.

On the other hand, OH^{-} will have both lone pair of electrons and a negative charge. Hence, its electron density is much more as compared to NH_{3} that only contains a lone pair of electron.

Therefore, NH_{3} will act as a weak base as compared to OH^{-}.

Thus, we can conclude that the statement OH^{-} is a stronger base than NH_{3}, is true concerning an aqueous solution of the weak base NH_{3}.

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igor_vitrenko [27]

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3 0
3 years ago
2a. Density is the relationship between mass and volume. Density has
Charra [1.4K]

The volume of copper : 3.24 ml

<h3>Further explanation </h3>

Density is a quantity derived from the mass and volume

Density is the ratio of mass per unit volume

With the same mass, the volume of objects that have a high density will be smaller than objects with a smaller type of mass

The unit of density can be expressed in g/cm³ or kg/m³

Density formula:

\large{\boxed {\bold {\rho~=~ \frac {m} {V}}}}

ρ = density , g/cm³ or kg/m³

m = mass , g or kg

v = volume , cm³  or m³

A common example is the water density of 1 gr / cm³

The density of copper : 8.96 gr/ml

mass of copper : 29 g

then the volume :

\tt V=\dfrac{m}{\rho}\\\\V=\dfrac{29~g}{8.96~g/ml}\\\\V=\boxed{\bold{3.24~ml~or~3.24~cm^3}}

8 0
3 years ago
What is the mass percent of potassium sulfate in solution if 78g of potassium sulfate is dissolved in 500 mL of water? (The dens
Debora [2.8K]

Answer:

13.5 %

Explanation:

First we<u> calculate the mass of 500 mL of water</u>, using <em>its density</em>:

  • Volume * Density = Mass
  • 500 mL * 1.00 g/mL = 500 g

Then we <u>calculate the mass percent of potassium sulfate</u>, using the formula:

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6 0
2 years ago
Osmosis is the process responsible for carrying nutrients and water from groundwater supplies to the upper parts of trees. The o
liberstina [14]

Answer: Molar concentration of the tree sap have to be 0.783 M

Explanation:

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

\pi=iCRT

where,

\pi = osmotic pressure of the solution = 19.6 atm

i = Van't hoff factor = 1 (for non-electrolytes)

R = Gas constant = 0.0821\text{ L.atm }mol^{-1}K^{-1}

T = temperature of the solution = 32^oC=[273+32]=305K

Putting values in above equation, we get:

19.6atm=1\times C\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 305K

C=0.783M

Thus the molar concentration of the tree sap have to be 0.783 M to achieve this pressure on a day when the temperature is 32°C

4 0
3 years ago
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