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NNADVOKAT [17]
3 years ago
11

¿A qué grupo pertenecen los átomos de Z = 8, Z= 36 y Z=39? ¿Cuántas capas de electrones tiene cada uno? ¿Cuántos electrones harí

an falta para llenar la capa más externa?
Chemistry
1 answer:
zaharov [31]3 years ago
3 0

Answer:

Mira la explicación.

Explanation:

¡Hola!

En este caso, podemos encontrar facilmente el grupo al que pertenecen dichos elementos con números atómicos 8, 36 y 39 respectivamente mediante su búsqueda en la tabla periódica. Así, z=8 corresponde a oxígeno, z=36 a kriptón y z=39 a itrio.

Por otro lado, para saber el número de capas, debemos desarrollar la configuración electrónica para cada uno:

O: 1s^2,2s^2,2p^4\\Kr: 1s^2,2s^2,2p^6,3s^2,3p^6,4s^2,3d^{10},4p^6\\Y:1s^2,2s^2,2p^6,3s^2,3p^6,4s^2,3d^{10},4p^6,5s^2,4d^1

Con esto, vemos que oxígeno tiene dos capas, kripton cuatro capas e iritrio cinco, a lo que a oxígeno le faltan dos electrones para llenar dicha capa, a kripton ninguno y a iritrio nueve.

Saludos.

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How many moles of O2 are required to react with 6.6 moles of H2?
Bingel [31]

<u>Answer: </u>

<u>For 1:</u> 3.3 moles of oxygen gas is required.

<u>For 2:</u> 14 moles of hydrogen gas is required.

<u>For 3:</u> 1.5 moles of oxygen gas is required.

<u>Explanation:</u>

The chemical reaction of oxygen and hydrogen to form water follows:

O_2+2H_2\rightarrow 2H_2O

  • <u>For 1:</u> When 6.6 moles of H_2 is reacted.

By Stoichiometry of the above reaction:

2 moles of hydrogen gas reacts with 1 mole of oxygen gas.

So, 6.6 moles of hydrogen gas will react with = \frac{1}{2}\times 6.6=3.3mol of oxygen gas.

Hence, 3.3 moles of oxygen gas is required.

  • <u>For 2:</u> When 7.0 moles of O_2 is reacted.

By Stoichiometry of the above reaction:

1 mole of oxygen gas reacts with 2 moles of hydrogen gas.

So, 7 moles of oxygen gas will react with = \frac{2}{1}\times 7=14mol of hydrogen gas.

Hence, 14 moles of hydrogen gas is required.

  • <u>For 3:</u> When 3.0 moles of H_2O is formed.

By Stoichiometry of the above reaction:

2 moles of water is formed from 1 mole of oxygen gas.

So, 3.0 moles of water will be formed from = \frac{1}{2}\times 3.0=1.5mol of oxygen gas.

Hence, 1.5 moles of oxygen gas is required.

7 0
3 years ago
Methods: Part A: Preparation of Buffers Make two buffers starting with solid material, which is the most common way to make buff
Alecsey [184]

Answer:

0,542 g of Na₂HPO₄ and 0,741 g of NaH₂PO₄.

0,856 g of Tris-HCl and 0,553 g of Tris-base

Explanation:

It is possible to use Henderson–Hasselbalch equation to estimate pH in a buffer solution:

pH = pka + log₁₀ \frac{A^{-} }{HA}

Where A⁻ is conjugate base and HA is conjugate acid

The equilibrium of phosphate buffer is:

H₂PO₄⁻ ⇄ HPO4²⁻ + H⁺    Kₐ₂ = 6,20x10⁻⁸; <em>pka=7,21</em>

Thus, Henderson–Hasselbalch equation for phosphate buffer is:

pH = 7,21 + log₁₀ \frac{HPO4^{2-} }{H2PO4^{-} }

If desire pH is 7,0 you will obtain:

<em>0,617 =  \frac{HPO4^{2-} }{H2PO4^{-} } </em><em>(1)</em>

Then, if desire concentration of buffers is 0,10 M:

0,10 M = [HPO₄²⁻] + [H₂PO₄⁻] <em>(2)</em>

Replacing (1) in (2) you will obtain:

<em>[H₂PO₄⁻] = 0,0618 M</em>

And with this value:

<em>[HPO₄²⁻] = 0,0382 M</em>

As desire volume is 100mL -0,1L- the weight of both Na₂HPO₄ and NaH₂PO₄ is:

Na₂HPO₄ = 0,1 L× \frac{0,0382mol}{1L}× \frac{141,96g}{1mol} = 0,542 g of Na₂HPO₄

NaH₂PO₄ = 0,1 L× \frac{0,0618mol}{1L}× \frac{119,96g}{1mol} = 0,741 g of NaH₂PO₄

For tris buffer the equilibrium is:

Tris-base + H⁺ ⇄ Tris-H⁺ pka = 8,075

Henderson–Hasselbalch equation for tris buffer is:

pH = 8,075 + log₁₀ \frac{Tris-base }{Tris-H^{+} }

If desire pH is 8,0 you will obtain:

<em>0,841 =  \frac{Tris-base }{TrisH^{+} } </em><em>(3)</em>

Then, if desire concentration of buffers is 0,10 M:

0,10 M = [Tris-base] + [Tris-H⁺] <em>(4)</em>

Replacing (3) in (4) you will obtain:

[Tris-HCl] = 0,0543 M

[Tris-base] = 0,0457 M

As desire volume is 100mL -0,1L- the weight of both Tris-base and Tris-HCl is:

Tris-base = 0,1 L× \frac{0,0457mol}{1L}× \frac{121,1g}{1mol} = 0,553 g of Tris-base

Tris-HCl = 0,1 L× \frac{0,0543mol}{1L}× \frac{157,6g}{1mol} = 0,856 g of Tris-HCl

I hope it helps!

8 0
3 years ago
Which process results in the formation of sedimentary rocks?
klio [65]

Answer:

A. Rock fragments are layered and pressurized over time.

Explanation:

Sedimentary rocks are derived from pre-existing rocks that have been subjected to agents of denudation, weathered, transported and deposited within a basin.

In the basin, the sediments are accumulated in their final resting position.

  • Sediments are accumulated as layers on top of one another.
  • The pressure of the sediment on top of another forces out water and presses the layers into sheets.
  • Over time, the compression leads to lithification of the rock.
  • During lithification, compaction and cementation occurs.
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When an electron in an atom moves from high to low
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Answer:energy is emitted as electromagnetic radiy

Explanation:

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