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2 years ago

How many feet are in 2,241 inches? (1 foot = 12 inches)

2 answers:

8 0

Answer: A) 186.75 feet

Step-by-Step Explanation:

1 foot = 12 inches
1 inch = 1/12 foot

Therefore, Inches to Feet :-
= 2241/12
= 186.75 feet

maksim [4K]2 years ago

8 0

A- 186.75 feet

explanation: it just is because if you do the math

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The ratio of isabellas money to shanes money is 3:11. If isabella has $33, how much money do Shane and Isabella have together?

solong [7]

The ratio of Isabella’s money to Shane’s money is 3:11

Isabella has $33.

We can make a proportion to solve for how much money Shane has.
A proportion is two ratios that are set equal to each other.

Let’s call Shane’s money ‘S’

We get this proportion:   3/11 = 33/x

If we cross multiply we get:
(33) * (11) = (3) * (x)

Simplifying it, we get:
363 = (3) * (x)

Divide both sides by 3, we get:
x = 121

However, the question asks how much money they have together.

Isabella + Shane = Total
33 + 121 = $154

<span>They have $154 together.</span>

4 0

3 years ago

Please simplify n-2/n^2-4

Doss [256]

Answer:

$\frac{1}{ {n} + {2}}$

Step-by-step explanation:

$\frac{n - 2}{ {n}^{2} - 4} \\ \\ = \frac{n - 2}{ {n}^{2} - {2}^{2} } \\ \\ = \frac{n - 2}{ ({n} + {2})({n} - {2})} \\ \\ = \frac{1}{ {n} + {2}} \\$

8 0

3 years ago

Can some help me out with this EXTRA POINTS!!

Butoxors [25]

Answer: ≈ 185.73009

Step-by-step explanation:

area of square: $length^{2}$

area of circle: $\frac{radius^{2} * \pi }{y}$

length: 15

radius = diameter/2

radius: 5

area of square - area of circle = area between square and circle:

$15^{2} - \frac{5^{2} * \pi }{2} = 225 - \frac{25\pi}{2}$ ≈ 185.73009

hope it helps!

Please mark as brainliest.

8 0

2 years ago

Approximate f by a Taylor polynomial with degree n at the number a. Step 1 The Taylor polynomial with degree n = 3 is T3(x) = f(

MAVERICK [17]

Answer:

If you center the series at x=1

$T_3(x) = e^2 + 4e^2 (x-1)+10(x-1)^2 + \frac{56}{3} e^2(x-1)^3 + R(x)$

Where $R(x)$ is the error.

Step-by-step explanation:

From the information given we know that

$f(x) = e^{2x^2}$

$f'(x) = 4x e^{2x^2}$ (This comes from the chain rule )

$f^{(2)}(x) = 4e^{2x^2} (4x^2+1)$ (This comes from the chain rule and the product rule)

$f^{(3)}(x) = 16xe^{2x^2}(4x^2 + 3)$ (This comes from the chain rule and the product rule)

If you center the series at x=1 then

$T_3(x) = e^2 + 4e^2 (x-1)+10(x-1)^2 + \frac{56}{3} e^2(x-1)^3 + R(x)$

Where $R(x)$ is the error.

3 0

3 years ago

A statistician calculates that 8% of Americans own a Rolls Royce. If the statistician is right, what is the probability that the

hichkok12 [17]

Answer:

0.007 = 0.7% probability that the proportion of Rolls Royce owners in a sample of 595 Americans would differ from the population proportion by more than 3%

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

A statistician calculates that 8% of Americans own a Rolls Royce.

This means that $p = 0.08$

Sample of 595:

This means that $n = 595$

Mean and standard deviation:

$\mu = p = 0.08$

$s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.08*0.92}{595}} = 0.0111$

What is the probability that the proportion of Rolls Royce owners in a sample of 595 Americans would differ from the population proportion by more than 3%?

Proportion above 8% + 3% = 11% or below 8% - 3% = 5%. Since the normal distribution is symmetric, these probabilities are equal, and so we find one of them and multiply by 2.

Probability the proportion is less than 5%:

P-value of Z when X = 0.05. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{0.05 - 0.08}{0.0111}$

$Z = -2.7$

$Z = -2.7$ has a p-value of 0.0035

2*0.0035 = 0.0070

0.007 = 0.7% probability that the proportion of Rolls Royce owners in a sample of 595 Americans would differ from the population proportion by more than 3%

8 0

3 years ago