Step-by-step explanation:
Quadrilateral ABCD is inscribed in a circle.
Opposite angles of a Quadrilateral are Supplementary.
We have two points so we can find the gradient using y1-y2/x1-x2
gradient = 21-27/2-8
= 1
we know the form for any linear equation is y = mx + c
we have m and a point so we can substitute in point (2,21) to find c
21 = 1 x 2 + c
c = 19
therefore, the equation is y = x + 19
When you multipy 1.229 x 15 your answer is 18.435. Rounding to the nearest cent will only include 2 numbers after the decimal. Looking at 18.435, the last number, 5 will round your answer to 18.44
Answer: -x+9
Step-by-step explanation:
Answer:
x = 31
Step-by-step explanation:
Given:
MN = 20
PQ = x
RS = 42
Required:
Value of x
SOLUTION:
In a trapezoid, the midsegment length equals the sum of both bases divided by 2
This implies that:
PQ = ½(MN + RS)
Plug in the values
x = ½(20 + 42)
x = ½(62)
x = 31
