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3 years ago

6

adult tickets to a football game were $3.25 and student tickets were $1.75 if 1,350 fans paid a total of$2,700 to attempt the ga

me . How many adults attended?

1 answer:

Arturiano [62]3 years ago

6 0

225 adults and 1125 students. use system of equations

3.25x + 1.75y = 2700
x + y = 1350

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According to the MIT Airline Data Project, American Airlines controlled 15.5% of the domestic market during a recent year. A ran

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Step-by-step explanation:

In this question, we are asked to use the binomial distribution to calculate the probability that 10 or fewer passengers from a sample of MIT data project sample were on American airline flights.

We proceed as follows;

The probability that a passenger was an American flight is 15.5%= 15.55/100 = 0.155

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The probability that he/she isn’t on the flight, let’s call this q

q =1 - p= 0.845

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What value is equivalent to 52 + 53 − 54? A) -475 B) -350 C) -125 D) 5

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None of these answer choices are correct. The answer would be 51. 52+53=105

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Answer:

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Step-by-step explanation:

We are given that Researchers claim that 8% of people have blue eyes. Suppose the researchers' claim is true. Mrs. Greene has a Geometry class with 40 students.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 40 students

r = number of success = exactly 5

p = probability of success which in our question is % of people

having blue eyes, i.e; 8%

<em>LET X = Number of students having blue eyes</em>

So, it means X ~ $Binom(n= 40,p=0.08)$

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