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Marina CMI [18]
3 years ago
14

As Evan goes down a hill on his skateboard, he is slowed down by air

Physics
1 answer:
kompoz [17]3 years ago
4 0

Answer:

A. Diagram A

Explanation:

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Imagine a third particle, which we will call a cyberon. It has three times the mass of an electron (3m). It has a positive charg
GalinKa [24]

Answer:

Explanation:

Let the potential difference between plate be V .

Electrical energy lost for cyberon = V x 3e

Kinetic energy lost by cyberon = kinetic energy gain by it

V x 3e = 1/2 x 3m x vc²

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1 = vc² / ve²

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6 0
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Neptune is approximately 4.5 billion kilometers from the sun. What is this distance in AU?
11111nata11111 [884]
Below are the choices that can be found from other source:

a. 0.3 AU 
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<span>c. 30 AU </span>
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Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.
8 0
4 years ago
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Which law of motion accounts for the following statement?
m_a_m_a [10]

First, you need forces attracting the Sun and Earth toward each other.  That's described by Newton's law of universal gravitation.

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4 0
3 years ago
Three objects having the same mass begin at the same height, and all move down the same vertical distance H. One falls straight
Mnenie [13.5K]

Answer:

Work done in all the three cases will be the same.

Explanation:

1) The free falling body has only one force acting on it, the gravitational force. The work done on the body = mgH (Gravitational potential energy)

2) There are two forces acting on the body going down on a frictionless inclined plane - gravity and the normal force. The gravitational potential energy will be the same. The work done due to the normal force is zero, since the direction of the force is perpendicular to the displacement. Hence, total work done on the body = mgH

3) In the case of the body swinging on the end of a string, the change in gravitational potential enrgy will once again be the same since difference in height is H. The additional force on the body is the tension due to the string. But the work done due to this force is <em>zero, </em>since the displacement of the body is perpendicular to the tension. Therefore, the total work done on the body is once again mgH.

4 0
3 years ago
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