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bija089 [108]
4 years ago
14

Which factor limits interference between waves? A constant phase relationship between waves Similar wave amplitudes Unequal wave

lengths Radiation through the same region
Physics
2 answers:
Alisiya [41]4 years ago
8 0

Answer:

similar wave amplitudes

Explanation:

When two waves travelling in the same medium have similar wave amplitudes they are less likely to interfere with each other destructively or constructively because the interference between waves occur when the amplitudes of the waves arrive a position in the medium in opposite directions hence they add up( superposition) or cancel each other out.

Hence if the waves have similar wave amplitudes the interference between the waves will be limited.

Nady [450]4 years ago
5 0

Answer:

Unequal Wavelengths

Explanation:

"To set up a stable and clear interference pattern, two conditions must be met: The sources of the waves must be coherent, which means they emit identical waves with a constant phase difference. The waves should be monochromatic - they should be of a single wavelength." So unequal wavelengths will limit the interference between the waves.

(I put this answer on the quiz and got it right also)

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The kinetic energy of a ball with a mass of 0.5 kg and a velocity of 10 m/s is
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8 0
4 years ago
⦁ A 68 kg crate is dragged across a floor by pulling on a rope attached to the crate and inclined 15° above the horizontal. (a)
GREYUIT [131]

Answer:

303.29N and 1.44m/s^2

Explanation:

Make sure to label each vector with none, mg, fk, a, FN or T

Given

Mass m = 68.0 kg

Angle θ = 15.0°

g = 9.8m/s^2

Coefficient of static friction μs = 0.50

Coefficient of kinetic friction μk =0.35

Solution

Vertically

N = mg - Fsinθ

Horizontally

Fs = F cos θ

μsN = Fcos θ

μs( mg- Fsinθ) = Fcos θ

μsmg - μsFsinθ = Fcos θ

μsmg = Fcos θ + μsFsinθ

F = μsmg/ cos θ + μs sinθ

F = 0.5×68×9.8/cos 15×0.5×sin15

F = 332.2/0.9659+0.5×0.2588

F =332.2/1.0953

F = 303.29N

Fnet = F - Fk

ma = F - μkN

a = F - μk( mg - Fsinθ)

a = 303.29 - 0.35(68.0 * 9.8- 303.29*sin15)/68.0

303.29-0.35( 666.4 - 303.29*0.2588)/68.0

303.29-0.35(666.4-78.491)/68.0

303.29-0.35(587.90)/68.0

(303.29-205.45)/68.0

97.83/68.0

a = 1.438m/s^2

a = 1.44m/s^2

7 0
3 years ago
Which value is equivalent to 7.2 kilograms? A. 720 grams B. 7,200 grams C. 72,000 grams D. 720 milligrams E. 7,200 milligrams
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1 kilogram = 1,000 grams
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