Electric field on the axis of ring on both sides is along the axial line
This electric field is away from the center on both sides
Now when an electron is placed on the axis of the ring then we will see that it will experience the electrostatic force on the electron.
The direction of force is always towards the center of the ring because here electron is a negatively charged particle and it will move opposite to the direction of electric field.
So as we release the electron from a distance of 30 cm the electron will move towards the center of ring and accelerate to its maximum speed till it will reach to the center of the ring
After that the electron will reach to the center of the ring and then moves out on the opposite side and then decelerate to zero speed as it will reach on other side.
Now after this it will again move towards the center of the ring and continue its motion similar way
So this is an oscillating motion about the center of the ring.
<span>If you apply 100.0 N of force to lift an object with a single, fixed pulley, then the resistive force is also equivalent to 100 Newtons of force. Since the weight of the object was not mentioned, it is assumed that it has already been taken into account in the 100 N value of force. This follows Newton's law of motion of equal action and reaction.</span>
The net electric force acting on a positive test charge at the origin is determined as ¹/₉(kq₁q₂).
<h3>
Net electric force on the charges</h3>
The net electric force on the charges is calculated as follows;
F = kq₁q₂/r²
where;
- k is coulomb's constant
- q₁ and q₂ are the charges
- r is the distance between the charges
<h3>Distance between the charges</h3>
Thus, the net electric force acting on a positive test charge at the origin is determined as ¹/₉(kq₁q₂).
Learn more about electric force here: brainly.com/question/17692887
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Answer:
Explanation:
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Answer:
D
Explanation:
Let’s calculate the kinetic energy for all of the choices.
a. (1/2)(100)(100)^2 = 50(10000)=500,000
b. (1/2)(100)(1)^2 = 50
c. (1/2)(10)(100)^2 = 5(10000) = 50,000
d. (1/2)(1)(1)^2 = 0.5
We can see that (d) has the least kinetic energy.
