I think the answer would be 38in^2
Because the equation is : (a+b) *h / 2
A and b are both the bases of the trapezium
So (11 + 8) these are the bases and the height is 4 so you would do
(11+8)*4 / 2
(19)*4 / 2
76 / 2
= 38
When I factor[ 2cos (square) - 5cos -3], I get (2cos + 1)(cos - 3). 2cos + 1 = 0, 2cos = -1, cos = -0.5,. Using inv cos on calculator, I get 120 degree related angle.
Answer:
55.734 mph
Step-by-step explanation:
Let's call the wind speed x and the time of flight t.
Then, we can write the following equation, knowing that the distance is equal speed times time of flight:
910 = (350+x) * t
660 = (350-x) * t
If we isolate t in both equations and compare its value, we have that:
910 / (350+x) = 660 / (350-x)
(350+x)/(350-x) = 910/660
350 + x = 1.3788 * (350-x)
350 + x = 482.58 - 1.3788x
2.3788x = 132.58
x = 55.734 mph
Answer- Option 2
I hope that helps
Answer: #1 Answer is D
Step-by-step explanation: Welcome!
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