Answer:
0.345
Step-by-step explanation:
Use binomial probability:
P = nCr pʳ qⁿ⁻ʳ
where n is the number of trials,
r is the number of successes,
p is the probability of success,
and q is the probability of failure (1−p).
n = 5, r = 2, p = 0.41, and q = 0.59.
P = ₅C₂ (0.41)² (0.59)⁵⁻²
P = 0.345
Answer:
Prepositions
Step-by-step explanation:
Prepositions are usually used in front of nouns or pronouns and they show the relationship between the noun or pronoun and other words in a sentence
I got y^2/2
My Solution:
√9^2/18 · y^2
= 1/2 y^2
Multiply Fractions: a · (b/c) = (a · b)/c
1·y^2/2
=y^2/2
Hope I helped,
Faith xx
The table is a linear regression model, and the equation of the regression model is y = 0.24x + 0.77
<h3>The scatter plot that represents the table</h3>
See attachment for the required scatter plot
<h3>The best model of the scatter plot</h3>
From the attached scatter plot, we can see that the points are almost on a straight line
Hence, the best model that fits the scatter plot is a linear model
<h3>The equation of the regression model</h3>
Using a graphing calculator, we have the following calculation summary:
- Sum of x = 28
- Sum of y = 12.1
- Mean X = 4
- Mean Y = 1.7286
- Sum of squares (SSX) = 28
- Sum of products (SP) = 6.7
- b = SP/SSX = 6.7/28 = 0.23929
- a = MY - bMX = 1.73 - (0.24*4) = 0.77143
The regression equation is represented as:
y = bx + a
So, we have:
y = 0.23929x + 0.77143
Approximate
y = 0.24x + 0.77
Hence, the equation of the regression model is y = 0.24x + 0.77
Read more about regression models at:
brainly.com/question/13345245
#SPJ1
Answer:
120 pounds
Step-by-step explanation:
We can use systems of equations to solve this problem. Assuming j is Jim's weight and b is Bob's weight, the equations are:
j + b = 180
b - j = 1/2b
Let's get b - j = 1/2b into standard form (b, then j, then the equal sign, then the constant.)

Now we can solve using the process of elimination.

Now we know how much Bob weighs, for fun, let's find Jim's weight by substituting into the equation.

So Bob weighs 120 pounds and Jim weight 60 pounds.
Hope this helped!