Question

(a³-64)÷(a-4) dividing polynomials​

Answer 1

Answer:

$\textbf{ a^2 + 4a + 16 }$

Step-by-step explanation:

$\textup{Given:}\\ \frac{a^3 - 64}{a - 4} \\\textup{This can be written as:}\\ (a - 4)(a^2 + 4a + 16) \hspace{25mm} [ (a^3 - b^3) = (a - b)(a^2 + ab + b^2)]$

$\textup{Here b = 4 }\\\textup{Now, it can be written as}\\ \frac{(a - 4)(a^2 + 4a + 16)}{a - 4} \\\textup{which renders us}$

$a^2 + 4a + 16$