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2 years ago

2+3=8, 3+7=27, 4+5=32, 5+8=60, 6+7=72, 7+8=?? Solve it

Mathematics

2 answers:

alisha [4.7K]2 years ago

7 0

Answer:

2+3=2*[3+(2-1)]=8

3+7=3*[7+(3-1)]=27

4+5=4*[5+(4-1)]=32

5+8=5*[8+(5-1)]=60

6+7=6*[7+(6-1)]=72

therefore

7+8=7*[8+(7-1)]=98

x+y=x[y+(x-1)]=x^2+xy-x

weqwewe [10]2 years ago

4 0

Answer:

2*3 + 3* 7 = 27

4*3 + 5* 4 = 32

....

7*6 + 8*7 = 98

or it could be :

2+3-1 = 5 -1 = 4 *2 = 8

3+7-1 = 10-1 = 9 *3 = 27

4+5-1 = 9-1 = 8 * 4 = 32

5+8-1 = 13-1 = 12 * 5 = 60

6+7-1 = 13-1 = 12 *6 = 72

7+8-1 = 15-1 = 14*7 = 98

Step-by-step explanation:

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3 years ago

Read 2 more answers

the Following table shows alexandra's investment options over the course of three years. Her initial investment was $1,000 . wri

Y_Kistochka [10]

The pattern in the given series of amount in the account are in the form of

arithmetic and geometric progression.

The function for Option 1 is; $\underline{ f(n) = 1,100 + (n - 1) \cdot 100}$

The function for Option 2 is; $\underline{f(n) = 1,100 \times 1.1^{(n - 1)}}$

Reasons:

The given table of values is presented as follows;

$\begin{tabular}{c|c|c|c|}Number of years&1&2&3\\Option 1 (Amount in dollars)&1,100&1,200&1,300\\Option 2 (Amount in dollars)&1,100&1,210&1,331\end{array}\right]$

In Option 1, the amount in dollars for each year has a common difference of d = 100

The first term, a = 1,100

Therefore;

The Option 1 can be represented as an arithmetic progression , A.P. in the

form, tₙ = a + (n - 1)·d as follows;

For the Option 1, we have;

The amount in dollars after <em>n</em> years, $\underline{ f(n) = 1,100 + (n - 1) \cdot 100}$

For Option 2, it is possible to find;

1,331 ÷ 1,210 = 1,210 ÷ 1,100 = 1.1

Therefore;

The terms in the Option 2 have a common ratio of r = 1.1

The Option 2 is a geometric progression, G.P.

The first term in Option 2 is a = 1,100

Which gives, the nth term, tₙ = a·r⁽ⁿ ⁻ ¹⁾

Therefor;

The function for the Option 2 is; $\underline{f(n) = 1,100 \times 1.1^{(n - 1)}}$

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2 years ago

Help me please WITH NUMBER 7

Eva8 [605]

7a)
x - 10 + x - 11 + 3x + 6 = 180
5x -15 = 180
5x = 195
x = 39

7b)
y = 3x + 6
y = 3(39) +6
y = 117 + 6
y = 123

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3 years ago

Type the single exponent that would appear on the 7: *

liq [111]

You add the exponent. You never multiply it.

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2 years ago