2+3=8,
3+7=27,
4+5=32,
5+8=60,
6+7=72,
7+8=??
Solve it
2 answers:
Answer:
98
2+3=2*[3+(2-1)]=8
3+7=3*[7+(3-1)]=27
4+5=4*[5+(4-1)]=32
5+8=5*[8+(5-1)]=60
6+7=6*[7+(6-1)]=72
therefore
7+8=7*[8+(7-1)]=98
x+y=x[y+(x-1)]=x^2+xy-x
Answer:
2*3 + 3* 7 = 27
4*3 + 5* 4 = 32
....
7*6 + 8*7 = 98
or it could be :
2+3-1 = 5 -1 = 4 *2 = 8
3+7-1 = 10-1 = 9 *3 = 27
4+5-1 = 9-1 = 8 * 4 = 32
5+8-1 = 13-1 = 12 * 5 = 60
6+7-1 = 13-1 = 12 *6 = 72
7+8-1 = 15-1 = 14*7 = 98
Step-by-step explanation:
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Answer:
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When rolled 4 times, each time has a probability of 1/6
So the problem would be (1/6)^4.
