In rabbits, the allele for black fur, B, is dominant over the allele for brown fur,
2 answers:
Answer:
The correct answer would be C. 1/4
The genotype of both the parents is heterozygous that is, Bb.
So, both of them will produce two types of gametes one of which would contain B and the other one would contain b.
The cross would produce offspring with three possible types of genotypes; BB, Bb, and bb in the ratio 1:2:1.
The phenotype ratio would be 3(black): 1 (brown).
Thus, the probability of a homozygous dominant (BB) would be 1 out of 4.
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Answer:
1. 1/2
2. 1/2
3. 1/4
Explanation:
Let the allele for freckles be A or a while that of dimples be B or b.
A person without freckles but heterozygous for dimples = aaBb
A person who has freckles (whose mother has no freckles) but no dimples = Aabb
aaBb x Aabb
Offspring
4 AaBb - freckled and dimpled
4 Aabb - freckled and non dimpled
4 aaBb - non freckled and dimpled
4 aabb - non freckled and non dimpled
1. <em>Probability that the parents will have a dimpled child</em> = 8/16 or 1/2
2. <em>Probability that they will have a child with freckles</em> = 8/16 or 1/2
3. <em>Probability that they will have a child with freckles and dimples</em> = 4/16 or 1/4
<u>See the attached image for the Punnet's square analysis of the cross</u>
