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Lyrx [107]
3 years ago
8

40% of the memberships sold by Gym A were gold memberships.

Mathematics
1 answer:
Aneli [31]3 years ago
8 0

Answer:

a) If both gyms sold 80 total memberships, Gym A sold 12 more gold membership.

Step-by-step explanation:

Here is the complete question: 40% of the memberships sold by Gym A were gold memberships. 25% of the memberships sold by Gym B were gold memberships.  

Which statement must be true?

a) If both gyms sold 80 total memberships, Gym A sold 12 more gold membership.

b) If both gyms sold the same number of memberships, Gym A sold 15 more gold membership.

c) Gym A sold more gold membership than Gym A did.

d) If Gym B sold 50 membership, 25 would be gold memberships.

Given: Gym A have sold 40% gold membership of total membership.

Gym B have sold 25% gold membership of total membership.

Lets take option A first to find if it is true statement.

As per option A, There are total number of membership is 80.

∵ Gym A has sold 40% gold membership.

∴ Gym A gold membership= 40\% \times 80

⇒ Gym A gold membership= \frac{40}{100} \times 80= 32 member.

∴ Gym A gold membership= 32.

Now, Gym B

∵ Gym B has sold 25% gold membership.

∴ Gym B gold membership= 25\% \times 80

⇒ Gym B gold membership= \frac{25}{100} \times 80=20 member.

∴ Gym B gold membership= 20.

Next finding difference gold membership for Gym A and Gym B

32-20= 12 \ membership

Hence, we can say option A is correct as Gym A have sold 12 more gold membership, if total number of membership sold by both Gym is 80.

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