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tamaranim1 [39]
3 years ago
5

PLEASE HELP I NEED THIS QUICK IM SO STUCK.​

Mathematics
1 answer:
Katyanochek1 [597]3 years ago
6 0

Answer:

i think its A.

Step-by-step explanation:

y=5x is telling you that every hour, john jogs 5 miles, for example to solve for miles jogged in 3 hours for John you would use y=5(3), which is 15. If you graph John's equation, you would notice the point (1, 5), and on Tyrones graph, you see (1, 6) .  6 is one more than 5. not sureif that makes sense!

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Kiki divides 14 yard of tape into 4 equal pieces.<br><br> What is the length of each piece of tape?
lys-0071 [83]
3.5 each bc 4 * 3.5 is 14
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3 years ago
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95% of what number is 57? I need to find the whole number
algol [13]

Answer:

the correct answer is 60

8 0
3 years ago
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Which statement is true about the extreme value of the given quadratic equation? y = -3x2 + 12x − 33
Zina [86]

Answer:

The equation has a maximum value with a y-coordinate of -21.

Step-by-step explanation:

Given

y =-3x^2 + 12x - 33

Required

The true statement about the extreme value

First, write out the leading coefficient

Leading = -3

-3 < 0 means that the function would be a downward parabola;

Downward parabola always have their vertex on top of the parabola and as such, the function has a maximum value.

The maximum value is:

x = -\frac{b}{2a}

Where:

a= -3; b =12; c =-33

So, we have:

x = -\frac{12}{2 * -3}

x = -\frac{12}{-6}

x =2

Substitute x =2 in y =-3x^2 + 12x - 33

y = -3*2^2 + 12 * 2 - 33

y = -21

<em>Hence, the maximum is -21.</em>

8 0
3 years ago
manufacturing company produces digital cameras and claim that their products maybe 3% defective. A video company, when purchasin
alexdok [17]

Answer:

P(X>17) = 0.979

Step-by-step explanation:

Probability that a camera is defective, p = 3% = 3/100 = 0.03

20 cameras were randomly selected.i.e sample size, n = 20

Probability that a camera is working, q = 1 - p = 1 - 0.03 = 0.97

Probability that more than 17 cameras are working P ( X > 17)

This is a binomial distribution P(X = r) nCr q^{r} p^{n-r}

nCr = \frac{n!}{(n-r)!r!}

P(X>17) = P(X=18) + P(X=19) + P(X=20)

P(X=18) = 20C18 * 0.97^{18} * 0.03^{20-18}

P(X=18) = 20C18 * 0.97^{18} * 0.03^{2}

P(X=18) = 0.0988

P(X=19) = 20C19 * 0.97^{19} * 0.03^{20-19}

P(X=19) = 20C19 * 0.97^{19} * 0.03^{1}

P(X=19) = 0.3364

P(X=20) = 20C20 * 0.97^{20} * 0.03^{20-20}

P(X=20) = 20C20 * 0.97^{20} * 0.03^{0}

P(X=20) = 0.5438

P(X>17) = 0.0988 + 0.3364 + 0.5438

P(X>17) = 0.979

The probability that there are more than 17 working cameras should be 0.979 for the company to accept the whole batch

6 0
3 years ago
12 is what percent of 96
DaniilM [7]
12 * 100 = 1200/96 = 12.5 
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You mulitply 12 by a hunndred, since a percent means "out of a hundred." Then, you divide that, by 96, since, you want to find the percent out of 96.

8 0
3 years ago
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