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aivan3 [116]
3 years ago
7

Help me plzzzzzz!!!!!!!!!!!!

Mathematics
2 answers:
zysi [14]3 years ago
4 0
Open circle at ten going right
Eddi Din [679]3 years ago
3 0
I dont understand what I am supposed to do here
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Write the equation of a line in standard form that has x-intercept (P,0) and y-intercept (0,R).
ExtremeBDS [4]

Answer:

Rx+Py=RP

Step-by-step explanation:

The points on the straight line are (P, 0) and (0, R).

The slope would be

m=\frac{R-0}{0-P}=-\frac{R}{P}

And b=R, because the y-intercept is at (0, R).

So, the equation of this line would be

y=-\frac{R}{P} x+R

Where we multiply the equation by P

Py=-Rx+RP

Therefore, the equation that represents this line is

Rx+Py=RP

<h2>So, the right answer is B.</h2>
7 0
3 years ago
Please help with math question! This question is stressing me out (View Image)
TEA [102]
To find the volume of this one we need to break it down 
now i see half of a cylinder and rectangle:)
but first lets find the volume of the rectangle...
In order to find the Volume of a rectangle we need to use this formula...
Length x width x height 
in this case...
length = 10in
width = 6 in 
height = 8in
lets solve:)
10 x 6 x 8 = 480
or we write it like this 
480in³

now time to find the volume of the half cylinder:)
But first lets remember the volume for a cylinder
Volume = \pi r^{2} h
So lets find our measurements 
\pi = 3.14
r² = 5² or 25
h = 6 
so lets plug in our values just like our formula said:)
3.14 x 25 x 6 
now lets easily solve 
<span>3.14 x 25 x 6 = 471
</span>now since we found an entire cylinder and we only want half of a cylinder lets divide our answer in half
471 ÷ 2 = 235.5
so we write it like this 235.5units³
But we have to add both of our multiples together so lets do that
Volume of rectangle = <span>480in³
</span>volume of half sphere = 235.5units³
480 + 235.5 = 715.5
answer = 715.5units³
I hope this helped and everyone learned something new
anyways don't forget to
MARK ME BRAINLIEST! :D
3 0
3 years ago
What is 2 divided by 7
andrew11 [14]

Answer:

:)

Step-by-step explanation:

0.28571429

7 0
3 years ago
Read 2 more answers
For which system of equations is (5, 3) the solution? A. 3x – 2y = 9 3x + 2y = 14 B. x – y = –2 4x – 3y = 11 C. –2x – y = –13 x
Alla [95]
The <u>correct answer</u> is:

D) \left \{ {{2x-y=7} \atop {2x+7y=31}} \right..

Explanation:

We solve each system to find the correct answer.

<u>For A:</u>
\left \{ {{3x-2y=9} \atop {3x+2y=14}} \right.

Since we have the coefficients of both variables the same, we will use <u>elimination </u>to solve this.  

Since the coefficients of y are -2 and 2, we can add the equations to solve, since -2+2=0 and cancels the y variable:
\left \{ {{3x-2y=9} \atop {+(3x+2y=14)}} \right. &#10;\\&#10;\\6x=23

Next we divide both sides by 6:
6x/6 = 23/6
x = 23/6

This is <u>not the x-coordinate</u> of the answer we are looking for, so <u>A is not correct</u>.

<u>For B</u>:
\left \{ {{x-y=-2} \atop {4x-3y=11}} \right.

For this equation, it will be easier to isolate a variable and use <u>substitution</u>, since the coefficient of both x and y in the first equation is 1:
x-y=-2

Add y to both sides:
x-y+y=-2+y
x=-2+y

We now substitute this in place of x in the second equation:
4x-3y=11
4(-2+y)-3y=11

Using the distributive property, we have:
4(-2)+4(y)-3y=11
-8+4y-3y=11

Combining like terms, we have:
-8+y=11

Add 8 to each side:
-8+y+8=11+8
y=19

This is <u>not the y-coordinate</u> of the answer we're looking for, so <u>B is not correct</u>.

<u>For C</u>:
Since the coefficient of x in the second equation is 1, we will use <u>substitution</u> again.

x+2y=-11

To isolate x, subtract 2y from each side:
x+2y-2y=-11-2y
x=-11-2y

Now substitute this in place of x in the first equation:
-2x-y=-13
-2(-11-2y)-y=-13

Using the distributive property, we have:
-2(-11)-2(-2y)-y=-13
22+4y-y=-13

Combining like terms:
22+3y=-13

Subtract 22 from each side:
22+3y-22=-13-22
3y=-35

Divide both sides by 3:
3y/3 = -35/3
y = -35/3

This is <u>not the y-coordinate</u> of the answer we're looking for, so <u>C is not correct</u>.  

<u>For D</u>:
Since the coefficients of x are the same in each equation, we will use <u>elimination</u>.  We have 2x in each equation; to eliminate this, we will subtract, since 2x-2x=0:

\left \{ {{2x-y=7} \atop {-(2x+7y=31)}} \right. &#10;\\&#10;\\-8y=-24

Divide both sides by -8:
-8y/-8 = -24/-8
y=3

The y-coordinate is correct; next we check the x-coordinate  Substitute the value for y into the first equation:
2x-y=7
2x-3=7

Add 3 to each side:
2x-3+3=7+3
2x=10

Divide each side by 2:
2x/2=10/2
x=5

This gives us the x- and y-coordinate we need, so <u>D is the correct answer</u>.
7 0
4 years ago
BRAINLIEST LOL!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
egoroff_w [7]

Answer:

B

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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