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EleoNora [17]
3 years ago
13

The​ world's largest university​ (by enrollment) is University​ A, followed by University B. If the enrollment in University A i

s 3.5 million more students than University B and their combined enrollment is 9.5 million​ students, find the enrollment for each university?
Mathematics
1 answer:
Sav [38]3 years ago
8 0
Let x be the number of people at University B

x + (x+3.5) = 9.5
2x +3.5 = 9.5
2x = 6
x = 3 million students at University B

x + 3.5 = 3 + 3.5 = 6.5 million students at University A
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What is the coefficient of x4y4 in the expansion of (x + y)8?
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Answer:

70

Step-by-step explanation:

If you use Pascal's Triangle, you will need 9 lines, since there are 9 terms in a binomial raised to the 8th power.  Those 9 terms are:

1, 8, 28, 56, 70, 56, 28, 8, 1

The first expansion through the one we need are below (I hope you know how to use Pascal's Triangle!):

1(x^8)(y^0)+8(x^7)(y^1)+28(x^6)(y^2)+56(x^5)(y^3)+70(x^4)(y^4)+...

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3 years ago
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Plz help me with this
const2013 [10]

Answer:

x = 8

Step-by-step explanation:

We can add BA and AT together to find BT since we are finding the total length and the variable x.

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x = 8

Best of Luck!

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3 years ago
What is the product of a number and 3?
RideAnS [48]

The product is the result of multiplying, and whatever number is multiplied by 3 is the amount of times you add 3 to the answer.

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3 years ago
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In the game of​ roulette, a wheel consists of 38 slots numbered​ 0, 00,​ 1, 2,..., 36. To play the​ game, a metal ball is spun a
Oxana [17]

Answer:

E(X)=-0.0526

Sd(X)=5.763

Step-by-step explanation:

In statistics and probability analysis, the expected value "is calculated by multiplying each of the possible outcomes by the likelihood each outcome will occur and then summing all of those values".

The variance of a random variable Var(X) is the expected value of the squared deviation from the mean of X, E(X).

And the standard deviation of a random variable X is just the square root of the variance.  

Let X be a random variable which denotes the money you may win or lose on each spin.

In the game of roulette, a wheel consists of 38 slots. To play the game, a metal ball is spun around the wheel and is allowed to fall into one of the numbered slots. If the number of the slot the ball falls into matches the number you selected, we win $35; otherwise we lose $1.  So we have just one possibility to win and 37 of lose on an individual game.

___________________________

X            P(X)

___________________________

35           1/38

-1            37/38

___________________________

In order to calculate the expected value we can use the following formula:

E(X)=\sum_{i=1}^n X_i P(X_i)

And if we use the values obtained we got:

E(X)=(35)*(\frac{1}{38})+(-1)(\frac{37}{38})=-0.0526

In order to find the standard deviation we need to find first the second moment, given by :

E(X^2)=\sum_{i=1}^n X^2_i P(X_i)

And using the formula we got:

E(X^2)=(35^2)*(\frac{1}{38})+((-1)^2)(\frac{37}{38})=33.211

Then we can find the variance with the following formula:

Var(X)=E(X^2)-[E(X)]^2 =33.211-(-0.0526)^2 =33.208

And then the standard deviation would be given by:

Sd(X)=\sqrt{Var(X)}=\sqrt{33.208}=5.763

4 0
2 years ago
A service center receives an average of 0.6 customer complaints per hour. Management's goal is to receive fewer than three compl
True [87]

Answer:

0.18203 = 18.203% probability that exactly four complaints will be received during the next eight hours.

Step-by-step explanation:

We have the mean during a time-period, which means that the Poisson distribution is used to solve this question.

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

A service center receives an average of 0.6 customer complaints per hour.

This means that \mu = 0.6h, in which h is the number of hours.

Determine the probability that exactly four complaints will be received during the next eight hours.

8 hours means that h = 8, \mu = 0.6(8) = 4.8.

The probability is P(X = 4).

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 4) = \frac{e^{-4.8}*4.8^{4}}{(4)!} = 0.18203

0.18203 = 18.203% probability that exactly four complaints will be received during the next eight hours.

5 0
3 years ago
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