Answer:429.8 KW
Explanation:
carbon dioxide Inlet temperature
and pressure 100 KPa
At given Temperature and presssure ![c_p_1=0.846 kJ/kg-k](https://tex.z-dn.net/?f=c_p_1%3D0.846%20kJ%2Fkg-k)
Flow rate ![\dot{m} =1.5 kg/s](https://tex.z-dn.net/?f=%5Cdot%7Bm%7D%20%3D1.5%20kg%2Fs)
Steam Outlet temperature and Pressure is
and pressure is 600 KPa
![c_p_2=1.014 kJ/kg-k](https://tex.z-dn.net/?f=c_p_2%3D1.014%20kJ%2Fkg-k)
Heat loss 50 KW
Applying Steady Flow Energy Equation
![\dot{m}\left ( h_1+\frac{v_1^2}{2}+z_1 \right )+\dot{Q}=\dot{m}\left ( h_2+\frac{v_2^2}{2}+z_2 \right )+\dot{W}](https://tex.z-dn.net/?f=%5Cdot%7Bm%7D%5Cleft%20%28%20h_1%2B%5Cfrac%7Bv_1%5E2%7D%7B2%7D%2Bz_1%20%5Cright%20%29%2B%5Cdot%7BQ%7D%3D%5Cdot%7Bm%7D%5Cleft%20%28%20h_2%2B%5Cfrac%7Bv_2%5E2%7D%7B2%7D%2Bz_2%20%5Cright%20%29%2B%5Cdot%7BW%7D)
Neglecting Kinetic and Potential Energy changes
![\dot{m}h_1+\dot{Q}=\dot{m}h_2+\dot{W}](https://tex.z-dn.net/?f=%5Cdot%7Bm%7Dh_1%2B%5Cdot%7BQ%7D%3D%5Cdot%7Bm%7Dh_2%2B%5Cdot%7BW%7D)
![\dot{W}=\dot{m}\left ( c_p_1T_1-c_p_2T_2\right )+\dot{Q}](https://tex.z-dn.net/?f=%5Cdot%7BW%7D%3D%5Cdot%7Bm%7D%5Cleft%20%28%20c_p_1T_1-c_p_2T_2%5Cright%20%29%2B%5Cdot%7BQ%7D)
![\dot{W}=1.5\left ( 0.846\times 300-1.014\times 500\right )-50](https://tex.z-dn.net/?f=%5Cdot%7BW%7D%3D1.5%5Cleft%20%28%200.846%5Ctimes%20300-1.014%5Ctimes%20500%5Cright%20%29-50)
![\dot{W}=429.8 KW](https://tex.z-dn.net/?f=%5Cdot%7BW%7D%3D429.8%20KW)
Negative sign indicates work is being done on the system.
Answer:
969.68N
Explanation:
d₁=0.04 m A₁=![\frac{\pi d^2_{1} }{4}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cpi%20d%5E2_%7B1%7D%20%20%7D%7B4%7D)
![A_{1} =\frac{\pi \times .04^2}{4}= 0.00125m^{2} \](https://tex.z-dn.net/?f=A_%7B1%7D%20%3D%5Cfrac%7B%5Cpi%20%5Ctimes%20.04%5E2%7D%7B4%7D%3D%200.00125m%5E%7B2%7D%20%5C)
d₂=0.02 m A₂=![\frac{\pi d^2_{2} }{4}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cpi%20d%5E2_%7B2%7D%20%20%7D%7B4%7D)
![A_{2} =\frac{\pi \times .02^2}{4}= 0.00031m^{2} \](https://tex.z-dn.net/?f=A_%7B2%7D%20%3D%5Cfrac%7B%5Cpi%20%5Ctimes%20.02%5E2%7D%7B4%7D%3D%200.00031m%5E%7B2%7D%20%5C)
Q=1.2m³/min Q=1.2/60=0.02m³/s
using continuity equation
Q₁=A₁v₁
v₁=Q₁/A₁=0.02/0.00125=16m/s
Q₂=A₂v₂
v₂=Q₂/A₂=0.02/0.00031=64.5m/s
![F_{inlet}=\rho A_{1}v_1^{2}](https://tex.z-dn.net/?f=F_%7Binlet%7D%3D%5Crho%20A_%7B1%7Dv_1%5E%7B2%7D)
![F_{inlet}=1000\times 0.00125\times16^{2}=320N](https://tex.z-dn.net/?f=F_%7Binlet%7D%3D1000%5Ctimes%200.00125%5Ctimes16%5E%7B2%7D%3D320N)
![F_{outlet}=\rho A_{2}v_2^{2}](https://tex.z-dn.net/?f=F_%7Boutlet%7D%3D%5Crho%20A_%7B2%7Dv_2%5E%7B2%7D)
![F_{outlet}=1000\times 0.00031\times64.5^{2}=1289.68N](https://tex.z-dn.net/?f=F_%7Boutlet%7D%3D1000%5Ctimes%200.00031%5Ctimes64.5%5E%7B2%7D%3D1289.68N)
Force on the nozzle=F_{outlet}-F_{inlet}
= 1289.68-320
=969.68N
Answer:
a)Percent reduction in area=54.23 %
b)Percent elongation=32.87 %
Explanation:
Given that
Di= 11.53 mm
Df= 7.80 mm
Li= 51.4 mm
Lf= 68.3 mm
A= π/4 D²
a)
Percent reduction in area ,RA
![RA=\dfrac{A_i-A_f}{A_i}\times 100](https://tex.z-dn.net/?f=RA%3D%5Cdfrac%7BA_i-A_f%7D%7BA_i%7D%5Ctimes%20100)
![RA=\dfrac{D_i^2-D_f^2}{D_i^2}\times 100](https://tex.z-dn.net/?f=RA%3D%5Cdfrac%7BD_i%5E2-D_f%5E2%7D%7BD_i%5E2%7D%5Ctimes%20100)
![RA=\dfrac{11.53^2-7.8^2}{11.53^2}\times 100](https://tex.z-dn.net/?f=RA%3D%5Cdfrac%7B11.53%5E2-7.8%5E2%7D%7B11.53%5E2%7D%5Ctimes%20100)
RA= 54.23 %
Percent reduction in area=54.23 %
b)
Percent elongation EL
![EL=\dfrac{L_f-L_i}{L_i}\times 100](https://tex.z-dn.net/?f=EL%3D%5Cdfrac%7BL_f-L_i%7D%7BL_i%7D%5Ctimes%20100)
![EL=\dfrac{68.3-51.4}{51.4}\times 100](https://tex.z-dn.net/?f=EL%3D%5Cdfrac%7B68.3-51.4%7D%7B51.4%7D%5Ctimes%20100)
EL=32.87 %
Percent elongation=32.87 %
The net resultant direct force and angle on the vane is created when the water jet exits the vane at position 2 with 92% of its initial velocity.
<h3>What is mean by velocity?</h3>
- The speed at which a body or object is moving determines its direction of motion. A scalar quantity, speed is primarily. As a matter of fact, velocity is a vector quantity.
- The rate at which distance changes is what it is. It measures the displacement's rate of change. A body's velocity is defined as its speed in a particular direction.
- Velocity is a measure of how quickly a distance changes in relation to time. Having both magnitude and direction, velocity is a vector quantity.
- The rate of change in a body's displacement with respect to time is referred to as velocity. In the SI, m/s is its unit.
Given,
External angle of Curved Vane = 158°
mean velocity at 1 = 12 m/s
Volumetric flow rate = ![55 \mathrm{~m}^3 / \mathrm{h}=\frac{55}{3600} \mathrm{~m}^3 / \mathrm{s}$.](https://tex.z-dn.net/?f=55%20%5Cmathrm%7B~m%7D%5E3%20%2F%20%5Cmathrm%7Bh%7D%3D%5Cfrac%7B55%7D%7B3600%7D%20%5Cmathrm%7B~m%7D%5E3%20%2F%20%5Cmathrm%7Bs%7D%24.)
mean velocity at ![$2=12 \times 0.92=11.04 \mathrm{~m} / \mathrm{s}$](https://tex.z-dn.net/?f=%242%3D12%20%5Ctimes%200.92%3D11.04%20%5Cmathrm%7B~m%7D%20%2F%20%5Cmathrm%7Bs%7D%24)
i) Force exerted in x - friction A C 1 = Volume
![F_{S_x} &=\rho A C_1\left[C_2 \cos \theta-C_1\right] \\](https://tex.z-dn.net/?f=F_%7BS_x%7D%20%26%3D%5Crho%20A%20C_1%5Cleft%5BC_2%20%5Ccos%20%5Ctheta-C_1%5Cright%5D%20%5C%5C)
![&=1000 \times \frac{55}{3600}\left[\left(11.04 \cos 158^{\circ}\right)-12\right]](https://tex.z-dn.net/?f=%26%3D1000%20%5Ctimes%20%5Cfrac%7B55%7D%7B3600%7D%5Cleft%5B%5Cleft%2811.04%20%5Ccos%20158%5E%7B%5Ccirc%7D%5Cright%29-12%5Cright%5D)
i![\rangle F_{\text {sc }}=\supseteq A c_1\left[C_2 \sin \theta\right] \\](https://tex.z-dn.net/?f=%5Crangle%20F_%7B%5Ctext%20%7Bsc%20%7D%7D%3D%5Csupseteq%20A%20c_1%5Cleft%5BC_2%20%5Csin%20%5Ctheta%5Cright%5D%20%5C%5C)
![&=1000 \times \frac{55}{3600} \times \text { TI. 04 } \sin (1589 \\](https://tex.z-dn.net/?f=%26%3D1000%20%5Ctimes%20%5Cfrac%7B55%7D%7B3600%7D%20%5Ctimes%20%5Ctext%20%7B%20TI.%2004%20%7D%20%5Csin%20%281589%20%5C%5C)
![&F_{\text {syn }}=63.18 \mathrm{~N} \\](https://tex.z-dn.net/?f=%26F_%7B%5Ctext%20%7Bsyn%20%7D%7D%3D63.18%20%5Cmathrm%7B~N%7D%20%5C%5C)
![&\text { Angle } \Rightarrow \frac{F_{s y}}{F_{3 x}}-\tan \theta \\](https://tex.z-dn.net/?f=%26%5Ctext%20%7B%20Angle%20%7D%20%5CRightarrow%20%5Cfrac%7BF_%7Bs%20y%7D%7D%7BF_%7B3%20x%7D%7D-%5Ctan%20%5Ctheta%20%5C%5C)
![&\tan \theta=\frac{63.18}{339.18}, \theta=160-10-5.3 \\](https://tex.z-dn.net/?f=%26%5Ctan%20%5Ctheta%3D%5Cfrac%7B63.18%7D%7B339.18%7D%2C%20%5Ctheta%3D160-10-5.3%20%5C%5C)
![&\theta=\tan ^{-}\left(\frac{-63 \cdot 18}{339728}\right) \\](https://tex.z-dn.net/?f=%26%5Ctheta%3D%5Ctan%20%5E%7B-%7D%5Cleft%28%5Cfrac%7B-63%20%5Ccdot%2018%7D%7B339728%7D%5Cright%29%20%5C%5C)
![&\theta=-10.540^{\circ} \\](https://tex.z-dn.net/?f=%26%5Ctheta%3D-10.540%5E%7B%5Ccirc%7D%20%5C%5C)
The complete question is:
A horizontal jet of water strikes a curved vane as shown in Figure C.1. The external angle of the curved vane is 158°.The mean velocity and volumetric flow rate of the water jet at position 1 are 12 m/s and 55 m³/h respectively. Due to friction, the water jet leaves the vane at position 2 with 92 % its original velocity.
(i) Direct force exerted by the water jet on the vane in the x - direction.
(ii) Direct force exerted by the water jet on the vane in the y - direction.
(ii) Net resultant direct force and angle on the vane.
To learn more about velocity, refer to:
brainly.com/question/24681896
#SPJ4
Answer:
Access for physically disabled students and staff, fire hazards / fire escape hazards for stairs and elevators, emergency escapes...and that's all I can think of.