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Alekssandra [29.7K]
3 years ago
11

Define ways in which you would go about networking to explore opportunities in your career field and obtain more information for

yourself. If applicable, explain ways in which you have already done that and how you will expand going forward. Choose one person in your career field that you would like to have a conversation with. What do you think you can learn from this person?
Engineering
1 answer:
kkurt [141]3 years ago
6 0

Answer:

mmmmmm

Explanation:

ffmfmfmmfmfmmfmfmfmfmfmffmfmfmfmfmfmfmfmfmfmfmfmfffmmfmffmmmfmfmfmfmfmfmfmfffmfmfmfmfmfmmfmfmmfmfmfmfmfmfffmfmfffmfmfmfmffmmfmfmffmfmfmfmfffmfmfmfmfmmmmfmfmfmfmfmfmfmmmfmfmfmfmfmfmfmfmmfmfmfmfmfmfmfmfmfmfmffmfmfmfmfmfmmfmfmmmmmfmfmfmffmfmfmfmffmffmfm

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A column carries 5400 pounds of load and is supported on a spread footing. The footing rests on coarse sand. Design the smallest
Citrus2011 [14]

Answer:

Following are the responses to the given question:

Explanation:

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2 years ago
simple Brayton cycle using air as the working fluid has a pressure ratio of 10. The minimum and maximum temperatures in the cycl
Irina18 [472]

Answer:

a) 764.45K

b) 210.48 kJ/kg

c) 30.14%

Explanation:

pressure ratio = 10

minimum temperature = 295 k

maximum temperature = 1240 k

isentropic efficiency for compressor = 83%

Isentropic efficiency for turbine = 87%

<u>a) Air temperature at turbine exit </u>

we can achieve this by interpolating for enthalpy

h4 = 783.05 kJ/kg ( calculated in the background ) at state 4 using Table A-17  for  Ideal gas properties of air

T4 ( temperature at Turbine exit ) = 760 + ( 780 - 760 ) (\frac{783.05-778.18}{800.13-778.18} ) = 764.45K

<u>b) The net work output </u>

first we determine the actual work input to compressor

Wc = h2 - h1  ( calculated values )

     = 626.57 - 295.17 =  331.4 kJ/kg

next determine the actual work done by Turbine

Wt = h3 - h4  ( calculated values )

     = 1324.93 - 783.05 = 541.88 kJ/kg

finally determine the network output of the cycle

Wnet = Wt - Wc

         = 541.88 - 331.4  = 210.48 kJ/kg

<u>c) determine thermal efficiency </u>

лth = Wnet / qin  ------ ( 1 )

where ; qin = h3 - h2

<em>equation 1 becomes </em>

лth = Wnet / ( h3 - h2 )

      = 210.48 / ( 1324.93 - 626.57 )

      = 0.3014  =  30.14%

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3 years ago
Two Technicians are discussing ShopKey Pro. Technician
Leno4ka [110]

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Technician B

Explanation:

i took he test already

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True or False: The differential lock in an AWD-equipped vehicle can be used at any time.
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the answer would be false

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You guys are amazing :D
Sloan [31]
Ik i am thank you tho xoxo
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3 years ago
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