The tension in the rope when this bucket is suspended but stationery (static) is equal to 400 Newton.
<u>Given the following data:</u>
Mass = 40 kg.
<h3>How to calculate the tension?</h3>
Mathematically, the tension in the rope when this bucket is suspended but stationery (static) can be calculated by using this formula:
T = m(a + g)
<u>Note:</u> Acceleration due to gravity (g) is equal to 10 m/s² while the acceleration is 0 m/s² because the bucket is stationery (static)
Substituting the parameters into the formula, we have;
T = 40(0 + 10)
T = 400 Newton.
Read more on tension here: brainly.com/question/4080400
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Answer:
Fatigue lifetimes will be ranked as B>A>C
Explanation:
Start by calculating the mean stress for all samples
σa= (σamax + σamin)/2 = (450 - 350)/2 = 50MPa
σb= (σbmax + σbmin)/2 = (400 - 300)/2 = 50MPa
σa= (σcmax + σcmin)/2 = (340 - 340)/2 = 0MPa
Now calculate the stress amplitudes of all three samples
σa= (σamax - σamin)/2 = (450 + 350)/2 = 400MPa
σb= (σbmax - σbmin)/2 = (400 + 300)/2 = 350MPa
σc= (σcmax - σcmin)/2 = (340 + 340)/2 = 340MPa
The mean stress of samples A and B is the same which is higher than sample C. Hence samples A and B will have a higher fatigue life than sample C. However, the higher stress amplitude means lower fatigue life, hence, sample B will have a higher fatigue life than sample A. So the order will be B> A> C.
Attached picture shows the justification using and S- N plot.
Answer: Extension is Final length - initial length. This implies : 31.6-31 =0.6. Therefore the extension is 0.6
Explanation:
Answer:
By how it impacts our goals and the environment probably. Sorry if i'm wrong :(
B.) a short circuited loop of copper wire