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3 years ago

Help me with these questions plz

Mathematics

1 answer:

UkoKoshka [18]3 years ago

4 0

First, this shoudnt be in mathematics and second, i think this is socila studies.

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A can of soda is placed inside a cooler. As the soda cools, its temperature T (x) in degrees celsius is givien by the following

wel

Answer:

Initial 18 degrees Celsius

After 20 minutes, 5 degrees Celsius

Step-by-step explanation:

It’s initial temperature can be calculated as at the time when x = 0

When x = 0, the temperature is -6+24 = 18 degrees Celsius

This is because the exponent part equals 1 since anything raised in to the power of zero is one.

After twenty minutes,

T(x) = -6 +24e^-0.038(20)

T(x) = -6 + 11.224 = 5.224

And that is approximately 5 degrees Celsius to the nearest degree

8 0

3 years ago

The population of a local species of dragonfly can be found using an infinite geometric series where a1=42 and the common ratio

san4es73 [151]

$\bf \textit{sum of an infinite geometric serie}\\\\
\stackrel{for~~|r|\ \textless \ 1}{S=\sum\limits_{i=0}^{\infty}~a_1r^i\implies \cfrac{a_1}{1-r}}\qquad 
\begin{cases}
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
a_1=42\\
r=\frac{3}{4}
\end{cases}
\\\\\\
S=\cfrac{42}{1-\frac{3}{4}}\implies S=\cfrac{42}{\frac{1}{4}}\implies S=164$

bearing in mind that, the geometric sequence is "convergent" only when |r|<1, or namely "r" is a fraction between 0 and 1.

3 0

3 years ago

What is the volume of a square prism that is 4 centimeters by 4 centimeters by 8 centimeters

My name is Ann [436]

Answer:

138 is the answer

Step-by-step explanation:

128 square

6 0

3 years ago

he amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and s

sp2606 [1]

Complete question:

He amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and standard deviation 1.4 minutes. Suppose that a random sample of n equals 47 customers is observed. Find the probability that the average time waiting in line for these customers is

a) less than 8 minutes

b) between 8 and 9 minutes

c) less than 7.5 minutes

Answer:

a) 0.0708

b) 0.9291

c) 0.0000

Step-by-step explanation:

Given:

n = 47

u = 8.3 mins

s.d = 1.4 mins

a) Less than 8 minutes:

$P(X$

P(X' < 8) = P(Z< - 1.47)

Using the normal distribution table:

NORMSDIST(-1.47)

= 0.0708

b) between 8 and 9 minutes:

P(8< X' <9) = $[\frac{8-8.3}{1.4/ \sqrt{47}}< \frac{X'-u}{s.d/ \sqrt{n}} < \frac{9-8.3}{1.4/ \sqrt{47}}]$

= P(-1.47 <Z< 6.366)

= P( Z< 6.366) - P(Z< -1.47)

Using normal distribution table,

$NORMSDIST(6.366)-NORMSDIST(-1.47)$

0.9999 - 0.0708

= 0.9291

c) Less than 7.5 minutes:

P(X'<7.5) = $P [Z< \frac{7.5-8.3}{1.4/ \sqrt{47}}]$

P(X' < 7.5) = P(Z< -3.92)

NORMSDIST (-3.92)

= 0.0000

3 0

3 years ago

In a survey four out of every five people prefer creamy more then crunchy peanut butter. If there are 120 people at the grocery

JulsSmile [24]

Answer:

150

Step-by-step explanation:

set up a equation-

4/5=120/x

x= people buying peanut butter.

120/4=30

30 x 5=150

3 0

3 years ago