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aliina [53]
3 years ago
11

Please HElPPP I AM LITERALLY STUCK

Mathematics
1 answer:
Morgarella [4.7K]3 years ago
7 0
Please see attached photo and give brainliest if you can :) it took me a looong time, hope it helped :)

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Kristin charges $30 to train a small dog, and $50 to train a big dog. If Kristin trains 15 small dogs and 6 big dogs, how much m
tangare [24]

Answer:

$750

Step-by-step explanation:

We can set up the equation 30x + 50y =  z where x = the amount of small dogs, y = the amount of big dogs, and z = the total.

After plugging in the x and y values to solve for z, we are left with the following equation:

30(15) + 50(6) = 750

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when derek planted a tree it was 36 inches tall. the tree grew 1 1/4 inches per year the tree is now 44 3/4 inches tall. how man
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7 1/2 years ago to be precise

If correct brainley please

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2 years ago
How to factor by grouping
Ostrovityanka [42]
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6 0
3 years ago
Read 2 more answers
Evaluate the integral of the quotient of the cosine of x and the square root of the quantity 1 plus sine x, dx.
VMariaS [17]

Answer:

∫((cos(x)*dx)/(√(1+sin(x)))) = 2√(1 + sin(x)) + c.

Step-by-step explanation:

In order to solve this question, it is important to notice that the derivative of the expression (1 + sin(x)) is present in the numerator, which is cos(x). This means that the question can be solved using the u-substitution method.

Let u = 1 + sin(x).

This means du/dx = cos(x). This implies dx = du/cos(x).

Substitute u = 1 + sin(x) and dx = du/cos(x) in the integral.

∫((cos(x)*dx)/(√(1+sin(x)))) = ∫((cos(x)*du)/(cos(x)*√(u))) = ∫((du)/(√(u)))

= ∫(u^(-1/2) * du). Integrating:

(u^(-1/2+1))/(-1/2+1) + c = (u^(1/2))/(1/2) + c = 2u^(1/2) + c = 2√u + c.

Put u = 1 + sin(x). Therefore, 2√(1 + sin(x)) + c. Therefore:

∫((cos(x)*dx)/(√(1+sin(x)))) = 2√(1 + sin(x)) + c!!!

4 0
2 years ago
Read 2 more answers
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