answer
-8>0
step by step
-8:--------. NB you owe something or someone
0: you don't have anything or you don't owe anything
The part D is the correct one...
Answer:
a) 50.34% probability that the arrival time between customers will be 7 minutes or less.
b) 24.42% probability that the arrival time between customers will be between 3 and 7 minutes
Step-by-step explanation:
Exponential distribution:
The exponential probability distribution, with mean m, is described by the following equation:

In which
is the decay parameter.
The probability that x is lower or equal to a is given by:

Which has the following solution:

The probability of finding a value higher than x is:

Mean of 10 minutes:
This means that 
A. What is the probability that the arrival time between customers will be 7 minutes or less?


50.34% probability that the arrival time between customers will be 7 minutes or less.
B. What is the probability that the arrival time between customers will be between 3 and 7 minutes?





24.42% probability that the arrival time between customers will be between 3 and 7 minutes
It is 780.99999 sorry if i'm incorrect