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Elodia [21]
3 years ago
13

Compute the answers for this fish tank containing water.

Mathematics
1 answer:
ololo11 [35]3 years ago
7 0

Answer:

Option (3)

Step-by-step explanation:

Since density on an element = \frac{\text{Mass}}{\text{Volume}}

Volume of the water in the aquarium = volume of the aquarium

                                                              = Length × width × height

                                                              = 10 × 5 × 5

                                                              = 250 cm³

We know density of the water = 1 gram per cm³

By putting these values in the formula,

1 = \frac{\text{Mass}}{250}

Mass = 250 g

Therefore, Option (3) will be the answer.

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7(a−3+4b)

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4 0
3 years ago
Read 2 more answers
Find the volume of the composite figure below.
worty [1.4K]

Answer:

Volume of composit figure= 4834.14 cm^3

Step-by-step explanation:

here's your solution

=> Radius of hemisphere = 9 cm

==> volume of hemisphere = 2/3πr^3

==> volume of hemisphere = 2/3*22/7* 9^3

==> volume = 1526.04 cm^3

=> Radius of cylinder = 9 cm

=> Height of cylinder = 13 cm

==> volume of cylinder = πr^2h

==> volume of cylinder = 22/7*9^2*13

==> volume of cylinder = 3,308.1 cm^3

Volume of composit figure = 1526.04 + 3308.1

= 4834.14 cm^3

hope it helps

7 0
2 years ago
The triangles below are similar. Find x showing the proportion and all work.
zavuch27 [327]

we are given that

two triangles are similar

so, the  ratio of their sides must be same

we get

\frac{2}{6} =\frac{x}{x+2}

now, we can solve for x

step-1: Cross multiply both sides

2(x+2) =6x

step-2: Simplify left side

2x +4 =6x

step-3: Subtract both sides by 2x

2x +4-2x =6x-2x

4 =4x

step-4: Divide both sides by 4

x=1

so,

x=1............Answer

7 0
3 years ago
Reagan scored 1140 on the SAT. The distribution of SAT scores in a reference population is normally distributed with mean 1000 a
krok68 [10]

Answer:

Jessie scored higher than Reagan.

Step-by-step explanation:

We are given that Reagan scored 1140 on the SAT. The distribution of SAT scores in a reference population is normally distributed with mean 1000 and standard deviation 100.

Jessie scored 30 on the ACT. The distribution of ACT scores in a reference population is normally distributed with mean 17 and standard deviation 5.

For finding who performed better on the standardized exams, we have to calculate the z-scores for both people.

1. <u>Finding z-score for Reagan;</u>

Let X = distribution of SAT scores

SO, X ~ Normal(\mu=1000, \sigma^{2}=100^{2})

The z-score probability distribution for the normal distribution is given by;

                                    Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean = 1000

            \sigma = standard deviation = 100

Now, Reagan scored 1140 on the SAT, that is;

       z-score  =  \frac{1140-1000}{100}  =  1.4

2. <u>Finding z-score for Jessie;</u>

Let X = distribution of ACT scores

SO, X ~ Normal(\mu=17, \sigma^{2}=5^{2})

The z-score probability distribution for the normal distribution is given by;

                                    Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean = 17

            \sigma = standard deviation = 5

Now, Jessie scored 30 on the ACT, that is;

       z-score  =  \frac{30-17}{5}  =  2.6

This means that Jessie scored higher than Reagan because Jessie's standardized score was 2.6, which is 2.6 standard deviations above the mean and Reagan's standardized score was 1.4, which is 1.4 standard deviations above the mean.

6 0
3 years ago
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