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3 years ago

14

PLEASE HELP QUICKLY!!! How are average IQs related to normal distribution

1 answer:

katen-ka-za [31]3 years ago

6 0

Answer:

Read Explanation

Step-by-step explanation:

A standard devation of 15 means 68% of the norm group has scored between 85 (100 – 15) and 115 (100 + 15). In other words, 68% of the norm group has a score within one standard deviation of the average (100). Also, 95% of the norm group has an IQ score within two standard deviations of the average.

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Is there are 4 more girls than boys in ms. Raubs class of 28 students what is the ratio of girls to boys

Viefleur [7K]

The ratio of girls to boys would be 16:12 because if you divide 28 by 2 you get 14. subtract 2 to on one of them and add the two to the other. You get 12 and 16. There is a difference of 4 to them and when you add them together you get 28. :)

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3 years ago

A jar contains 0.85 liter of strawberry juice and 0.50 liter of mango juice. Celina poured 0.15 liter of watermelon juice into t

steposvetlana [31]

Original-drank+added=result

orignail=stwabery+mango+watermelon

original=0.85+0.50+0.15=1.5liter

drank=0.3

orignail-drank=result

1.5-0.3=drank=1.2liter

A. see above

B. addition and subtraction facts

3 0

3 years ago

Read 2 more answers

Help again quick please!

Dennis_Churaev [7]

Answer:

2/3

Step-by-step explanation:

5/6 - (1/8÷3/4)

=5/6 - (1/8 × 4/3)

=5/6 - ( 1/6)

=4/6

=2/3

8 0

2 years ago

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An 11-inch string is cut into 3 equal pieces. which expression shows the length of each piece?

vaieri [72.5K]

11 divided by 3 equals 3.66 repeating

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2 years ago

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Explain why f(x) = x^2+4x+3/x^2-x-2 is not continuous at x = -1.

liberstina [14]

Answer:

The value of x = -1 makes the denominator of the function equal to zero. That is why this value is not included in the domain of f(x)

Step-by-step explanation:

We have the following expression

$f(x) = \frac{x^2+4x+3}{x^2-x-2}$

Since the division between zero is not defined then the function f(x) can not include the values of x that make the denominator of the function zero.

Now we search that values of x make 0 the denominator factoring the polynomial $x^2-x-2$

We need two numbers that when adding them get as a result -1 and when multiplying those numbers, obtain -2 as a result.

These numbers are -2 and 1

Then the factors are:

$(x-2) (x + 1)$

We do the same with the numerator

$x^2+4x+3$

We need two numbers that when adding them get as a result 4 and when multiplying those numbers, obtain 3 as a result.

These numbers are 3 and 1

Then the factors are:

$(x+3)(x + 1)$

Therefore

$f(x) = \frac{(x+3)(x+1)}{(x-2)(x+1)}$

Note that $\frac{(x+1)}{(x+1)}=1$ only if $x \neq -1$

So since $x = -1$ is not included in the domain the function has a discontinuity in $x = -1$

3 0

3 years ago