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iogann1982 [59]
3 years ago
8

How many 4inch by 8inch bricks are needed to build a walk 6 feet wide and 24 feet long

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
5 0

Answer:

The number of bricks needed to build area of a walk is 648 .

Step-by-step explanation:

Given as :

The dimension of bricks is 4 inches by 8 inches

The Length of bricks = L = 4 inches

The width of bricks = w = 8 inches

So, Area of bricks = Length of brick  × width of brick

Or,  Area of bricks = 4 × 8

I.e  Area of bricks = 32 inches²

Again

The dimension of walk is 6 feet by 24 feet

The Length of walk = l = 6 feet = ( 6 × 12 ) inches

I.e Length of walk = 72 inches

The width of walk = 24 feet = ( 24 × 12 ) inches

I.e width of walk = 288 inches

So, Area of walk = Length of walk  × width of walk

Or,  Area of walk = 72 × 288

I.e  Area of walk = 20,736 inches²

Now , Let The number of bricks needed to build walk = n

So, n = \dfrac{\textrm Area of walk}{\textrm Area of bricks}

I.e n = \frac{20736 inches^{2}}{32 inches^{2}}

∴   n= 648

So, number of bricks needed = n = 648

Hence The number of bricks needed to build area of a walk is 648 . Answer

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