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VashaNatasha [74]
3 years ago
14

What is required of a proportional relationship that is not required of a general linear relationship?

Mathematics
1 answer:
Lana71 [14]3 years ago
8 0
The proportional relationship should require they y-intercept and is then 0 and the linear relationship should be in a straight line to be a linear! Hope this helps!
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HURRY I NEED HELP<br> I JUST NEED TO KNOW HOW TO DO THIS PLEASE <br> ILL GIVE 5 STARS AND STUFF PLS
timofeeve [1]

Answer:

On the left, it would be + 1 for each blank, and on the right it would also be +1 for each blank.

Step-by-step explanation:

They are asking for the intervals between each number.

Hope this helps!

3 0
2 years ago
6+-3= <br> Please help me
Brums [2.3K]

Answer:

3

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Write an equation for the line that goes through (-2,6) and is parallel to the line y=1/2x+9
katrin [286]

Answer:

y = 1/2x + 7

Step-by-step explanation:

Parallel lines have the same slope.

Therefore the new equation will have a slope(m) = 1/2

Substitute m = 1/2 and point (-2, 6) into y = mx + b to solve for "b"

y = mx + b

6 = 1/2(-2) + b

6 = -1 + b

7 = b

The new equation: y = mx + b

                                y = 1/2x + 7

7 0
3 years ago
WILL GIVE BRAINLIEST AND 50 POINTS!
Cerrena [4.2K]

Answer: The function M if derived from the integral of the derivative of the function. This is valid by the fundamental theorem of calculus.

M(x)=43x32−7x+C

Step-by-step explanation: not 100 about this but it's what I got

4 0
3 years ago
Find an equation of the line given one point and the slope. (–10, –5);
allochka39001 [22]
You forgot to provide the slope but here is how you do this 

the slope 5 = (y2 - y) / (x2 - x) but we know that (x2, y2) = (-10, -5)
=> (-5 - y) / (-10 - x) = 5 --- multiply both sides by (-10 - x)
=> (-5 - y) = 5 (-10 - x) 
=> (-5 - y) = -50 - (5)x --- add +5 to both sides 
=>  -y = (-50 + 5) - (5)x --- multiply both sides -1 
=> y = 5x + 45  --- this will be your equation. 
7 0
3 years ago
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