The volume formula of a cylinder is :
From the problem, the volume is 1 m^3 and the height is 0.6 m.
Substitute the given to the formula :
Take the square root of both sides of the equation :
![\begin{gathered} r^2=0.53 \\ r=\sqrt[]{0.53} \\ r=0.728 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20r%5E2%3D0.53%20%5C%5C%20r%3D%5Csqrt%5B%5D%7B0.53%7D%20%5C%5C%20r%3D0.728%20%5Cend%7Bgathered%7D)
The answer is r = 0.728 m
Answer:
x=-8, y=76/3
Step-by-step explanation:
I solved for substitution since I didn't know exactly what you're solving for.
9514 1404 393
Answer:
64k^6 -64k^5 +(80/3)k^4 -(160/27)k^3 +(20/27)k^2 -(4/81)k +1/729
Step-by-step explanation:
The row of Pascal's triangle we need for a 6th power expansion is ...
1, 6, 15, 20, 15, 6, 1
These are the coefficients of the products (a^(n-k))(b^k) in the expansion of (a+b)^n as k ranges from 0 to n.
Your expansion is ...
1(2k)^6(-1/3)^0 +6(2k)^5(-1/3)^1 +15(2k)^4(-1/3)^2 +20(2k)^3(-1/3)^3 +...
15(2k)^2(-1/3)^4 +6(2k)^1(-1/3)^5 +1(2k)^0(-1/3)^6
= 64k^6 -64k^5 +(80/3)k^4 -(160/27)k^3 +(20/27)k^2 -(4/81)k +1/729
Answer:
The food store used 3 lbs of clusters, 6 lbs of granola, and 3 lbs of raisins.
Step-by-step explanation:
Given that:
A food store makes a 12-lb mixture of granola, clusters, and raisins.
The cost of granola = 1.00 per pound
The cost of clusters = 3.00 per pound
The cost of raisins = 2.00 per pound
Let granola be = g; cluster be c and raisins be r
Then, g + c + r = 12
Similarly, the mixture calls for twice as much granola as clusters.
2c + c + r = 12
3c + r = 12
r = 12 - 3c
2c(1) + 3c + 2r = 21
2c + 3c + 2r = 21
5c + 2r = 21
5c + 2(12 -3c) = 21
5c + 24 - 6c = 21
24 - c = 21
-c = 21 - 24
c = 3
Thus, cluster c = 3 lbs
granola = 2(c) = 2(3) = 6 lbs
raisins = 12 - 3c
= 12 - 3(3)
= 12 - 9
raisins = 3 lbs
