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tatiyna
3 years ago
13

Eight more than the product of four and a number is twice the sum of the number and six. Write an equation that can be used to s

olve for this number. What is the number?​
Mathematics
1 answer:
masha68 [24]3 years ago
3 0
4n+8=2(n+6)
Now isolate the n on one side of the equation:
4n+8=2n+12(distribution of the 2)
4n=2n+4(combine like terms)
2n=4(combine like variables)
N=2(isolate the n)

The answer is 2
Good luck!
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Circumference and Area questions look at the picture
Helga [31]

Note that the formula for the circumference of a circle is πd, while the formula for the area of a circle is πr².

π≈3.14

A. C=πd

Simply plug in the numbers into the formula.

Diameter=Radius*2

17*2=34

C=34(π)

B. (π)(5²)

Plug in the numbers into the formula. Remember that half of the diameter is the radius.

C.  (π)(4.5)

There are two possible formulas that could be used to calculate the circumference of a circle: πd and 2πr.

The expression above is simply multiplying the circle's radius times pi. Therefore, it is not a method that could be used to find the circumference of a circle.

D. (π)(6.5²)

Remember that the formula for calculating the area of a circle is πr².

Half of the diameter is 6.5 (13.5/2=6.5). 6.5 cm. is the radius. Now just plug the numbers into the formula.

(π)(6.5²)

Therefore, the last answer choice is the correct answer.

5 0
3 years ago
Solve the proportion: 10/9=5/k​
pychu [463]

Answer:

k= 9/2

decimal form:4.5

mixed number: 4 1/2

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Use the rules of exponents to evaluate or simplify. Write without negative exponents 8-squr3 is the conjugate of 8+squar 3
NISA [10]
8 - sqrt(3) is indeed the conjugate of 8 + sqrt(3).

What are you asking here?  You are to "evaluate or simplify" what?
5 0
4 years ago
A skydiver weighing 180lbs (including equipment) falls vertically downward from an altitude of 5000 ft and opens the parachute a
Annette [7]

<span>For the presented problem, the solution would be</span><span> </span><span>v</span><span>(0)=0</span><span>v(0)=0</span><span> is</span><span>v</span><span>(</span><span>t</span><span>)−</span><span>mgb</span><span>=</span><span>e</span><span>−</span><span>b</span><span>/</span><span>m</span><span>⋅</span><span>t</span><span>(</span><span>v</span><span>0</span><span>−</span><span>mgb</span><span>)</span><span>⟺</span><span>v</span><span>(</span><span>t</span><span>)=</span><span>mgb</span><span>(</span><span>1−</span><span>e</span><span>−</span><span>b</span><span>/</span><span>m</span><span>⋅</span><span>t</span><span>)</span><span>≈</span><span>g</span><span>⋅</span><span>t</span><span>−</span><span>gb</span><span>2</span><span>m</span><span>⋅</span><span>t</span><span>2</span><span>, with the following given, </span><span>
m</span><span>=180[lb]=81.6[kg]</span><span> </span>

<span>g</span><span>=9.81[m/s</span><span>2</span><span>]</span><span />

<span>b</span><span>=0.75[kg</span><span>⋅</span><span>m/s</span><span>2</span><span>⋅</span><span>s/ft]=0.2286[kg/s]</span><span />

<span>The solution that the friction provides is </span><span>v</span><span>(</span><span>t</span><span>)=3501.7[m/s]</span><span>⋅</span><span>(</span><span>1−</span><span>e</span><span>−0.00280[1/s]</span><span>⋅</span><span>t</span><span>), where I get </span><span><span>96.69</span></span><span /><span><span><span><span>[</span></span><span /><span><span>m</span></span><span /><span><span><span><span>/</span></span></span></span></span><span><span><span>s</span></span><span /><span><span>]</span></span></span><span>=</span></span><span /><span><span>317.2</span></span><span /><span><span><span><span>[</span></span><span /><span><span>f</span><span>t</span></span><span /><span><span><span><span>/</span></span></span></span></span><span><span><span>s</span></span><span /><span><span>]</span></span></span></span><span><span /></span><span>. I am hoping that this answer has satisfied your query about this specific question.<span /></span>

7 0
3 years ago
Jamie needs to determine the distance across a river. She selects a rock, R, on the opposite river bank. She finds a tree, T, on
Setler [38]

Since RT is perpendicular to the river, you have that segment CT is perpendicular to RT and, thus, CT⊥RB, because point B lies in a straight line with points R and B. Angles TCR and TCB are congruent (she walks from C in a direction that makes the same angle as TCR with the river bank on her side of the river).

This means that triangle CRB is isosceles triangle with base BR and height CT, because height CT is also a bisector of angle BCR.

The height CT divides triangle BCR into two right triangles BCT and RCT, where:

  • CT is common leg;
  • ∠TCR≅∠TCB,

then by LA Theorem these two triangles are congruent (ΔBCT≅ΔRCT).

Congruent triangles have congruent corresponding sides:

  • BC≅RC;
  • CT≅CT;
  • BT≅TR.

If BT turns out to be 75 yards, then TR=75 yards.

By the Pythagorean theorem,

BC^2=CT^2+BT^2,\\ \\BC^2=50^2+75^2=2500+5625=8125,\\ \\BC=\sqrt{8125}=25\sqrt{13}.

If BC=25\sqrt{13}, then distance from the spot to the rock is  CR=25\sqrt{13}.

Answer: RT=75 yards, CR=25\sqrt{13} yards.

4 0
3 years ago
Read 2 more answers
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