Answer:
Step-by-step explanation:
first lets add our two given angles, 90 (the little square) and 146
146 + 90 = 236
then subtract that from 360 to get our missing angle
360 - 236 = 124
so your answer is 124 degrees
hope this helps <3
<h2>
Hello!</h2>
The answers are:
B. 
C. 
<h2>Why?</h2>
We can use the quadratic equation to find the two values of x that are roots of the given equation. We must remember that most of the quadratic equations have two roots, however, we could find quadratic equations with just one root or even with no roots, at least in the real numbers.
Quadratic equation:

So,
From the given equation we have:

Substituting it into the quadratic equation to find the roots, we have:

So,

Hence, the correct options are B and C.
Answer:

Step-by-step explanation:
we know that
The area of the figure is equal to the area of rectangle (figure 1) plus the area of trapezoid (figure 2)
see the attached figure to better understand the problem
The area of the rectangle is

The area of the trapezoid is
](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%5B%2815-9%29%2B3%29%5D%288-3%29)
=22.5\ cm^{2}](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%5B6%2B3%29%5D%285%29%3D22.5%5C%20cm%5E%7B2%7D)
The area of the figure is

Answer:
C 210
Step-by-step explanation:
To solve this, First we must take 42/3, Since it equals 14, we take 15x14 and find 210
(edit: to solve for Kim's missing values, you do the same with 2 and 32)
Answer:
The numbers associated with the triangle are 5.437 and 6.437 centimeters, respectively.
Step-by-step explanation:
Two numbers are consecutives, when their difference is equal to 1. The area of the triangle is determined by the following formula:



Where
is the shortest length of the triangle, measured in centimeters.
And we get the following second-order polynomial:
(1)
If we know that
, then the shortest length of the triangle is:
and 
Since length is a positive variable, the only possible solution is:

Then, the numbers associated with the triangle are 5.437 and 6.437 centimeters, respectively.